分解因式a4次方(b-c) b4次方(c-a) c4次方(a-b)
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a^4+b^4=(a²+b²)²-2a²b²a^4+b^4=(a²+b²+a•b•√2)•(a
(a-b)(c+d)-(a-b)(c-d)=(a-b)【(c+d)-(c-d)】=(a-b)2d=2ad-2bd
证明:a、b、c互不相等,由基本不等式,得:a^4+b^4+c^4=1/2(a^4+b^4+b^4+c^4+c^4+a^4)>1/2(2a²b²+2b²c²+2
【俊狼猎英】团队为您解答(a+b)的2次方-4b的2次方=(a+b+2b)(a+b-2b)=(a+3b)(a-b)
8A+B+C=0A=-B-CB^2+C^2+BC=2B^4+2B^3C+3B^2C^2+2BC^3+C^4=4A^4+B^4+C^4=2(B^4+2B^3C+3B^2C^2+2BC^3+C^4)=2*
上试化为A^4+B^4+C^4+D^4-4ABCD=0左边=A^4+B^4-2A^2B^2+C^4+D^4-2C^2D^2-4ABCD+2A^2B^2+2C^2D^2=(A^2-B^2)^2+(C^2
:(a-b)^2-c^2+4ab=a^2+b^2-2ab+4ab-c^2=a^2+2ab+b^2-c^2=(a+b)^2-c^2=(a+b+c)(a+b-c)
证明:∵a4+b4+c4+d4=4abcd,∴a4-2a2b2+b4+c4-2c2d2+d4+2a2b2-4abcd+2c2d2=0,(a2-b2)2+(c2-d2)2+2(ab-cd)2=0.a2-
(1)原式=5x(x-3)+2y(x-3)=(x-3)(5x+2y),(2)原式=3b[a3-(3b)3]=3b(a-3b)(a2+9b2-3ab).(3)原式=-(a4-24)=-(a2+4)(a-
a^4+b^4+c^4=1/2(a^4+b^4+a^4+c^4+b^4+c^4)≥1/2(2a^2*b^2+2a^2*c^2+2b^2*c^2)=a^2*b^2+a^2*c^2+b^2*c^2=1/2
m(a-b+c)-n(b-a-c)=m(a-b+c)+n(a+c-b)=(m+n)(a+c-b)
a^4+b^4+c^4=1/2(a^4+b^4+a^4+c^4+b^4+c^4)≥1/2(2a^2*b^2+2a^2*c^2+2b^2*c^2)=a^2*b^2+a^2*c^2+b^2*c^2=1/2
a+b+c=0(a+b+c)²=0a²+b²+c²=12(ab+ac+bc)=-1ab+ac+bc=-1/2(ab+ac+bc)²=1/4a²
a^4+b^4+c^4+2a²b²-2b²c²-2a²c²-4a²b²=(a^4+b^4+2a²b²
-a3次方c+a4次方b+a3次方;=-a^3(c-ab-1)-4a3次方+16a平方-26a=-2a(2a^2-8a+13)
4a^2b^3-6ab^2c+8ac=2a(2ab^3-3b^2c+4c)-1/6*x^3-0.5x^2+x=-1/6x(x^2+3x-6)
6a(b-2c)^3-9b(2c-b)^4=6a(b-2c)^3-9b(b-2c)^4=3(b-2c)^3[2a-3b(b-2c)]=3(b-2c)³(2a-3b²+6bc)
(a^2-ab)+c(a-b)=a(a-b)+c(a-b)=(a-b)(a+c)