化简2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy y²)]-搜答案-百度作业网

解2(x²-xy)-3(2x²-3xy)=(2x²-6x²)+(-2xy+9xy)=-4x²+7xy再问：��|-15|-8�£�-2��+4*�

因式分解x²-2xy-3x

因式分解x²-2xy-3x原式=x(x-2y-3)再问：这是最简的吗再答：对，只能分解到这个程度。

对.前提是x不等于y

3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy

3xy[2xy-x（y-2）+x]＝3xy[2xy-xy+2x+x]=3xy(xy+3x)=3x²y²+9x²y

x＾2-3xy／x＾2－6xy+9y＾2=x(x-3y)/(x-3y)^2=x/(x-3y)

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

-(x^2-2xy-y^2)+(5x^2-2xy-3y^2)=(-1+5)x^2+(2-2)xy+(1-3)y^2=4x^2-2Y^2

-3(2x²-xy)+4(x²+xy-6)

-3(2x²-xy)+4(x²+xy-6)=6x²+3xy+4x²+4xy-24=-2x²+7xy-24

2x²-3xy+(2xy-x²)=2x²-3xy+2xy-x²=x²-xy=x(x-y)

-3(2x^2-xy)+4(x^2+xy-6)

-3(2x^2-xy)+4(x^2+xy-6)=-6x^2+3xy+4x^2+4xy-24=-2x^2+7xy-24再问：thankyou~

原式=1-3xy+x+(-4x-6xy)=1-3xy+x-4x-6xy=1-3x-9xy

(3x^2+2xy)/xy-(2x^2-xy)/xy=(3x^2+2xy-2x^2+xy)/xy=(x^2+3xy)/xy=x(x+3y)/xy=(x+3y)/y

4xy-3y²-3x²+xy-3xy-2x²+x²-2y²=2xy-5y²-4x²再问：过程写的完整点谢谢，还有一题谢谢http:

[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/

-3{y-(3x^2-3xy)}-{y+2(4x^2-4xy)}=-3{y-3x^2+3xy}-{y+8x^2-8xy}=-3y+9x^2-9xy-y-8x^2+8xy=x^2-xy-4y

-7X平方+6(X平方-5XY)-2(3xy平方-X平方)=-7X平方+6X平方-30XY-6xy平方+2X平方=X平方-30XY-6xy平方

原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&

-(x²-2xy-y²)+(5x²-2xy-3y²)=-x²+2xy+y²+5x²-2xy-3y²=4x²-2

再答：望采纳，谢谢！可以继续追问哟^_^再问：过程再答：好的，马上哈再答：再答：就是合并同类项的意思再答：再答：好的，谢谢哈^_^