2x-9=3-x
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等于37因为:【】都是一样的数字的话那他们就可以合并同类项:[]{10+1}*5=1980所以算出为37~
(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么
原式=x³-6x²-9x-2x²+12x+18-(x²-5x)(x-3)=x³-8x²+3x+18-(x³-3x²-5x
是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)
设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y
1)(x-3)/(x-2)-(x-5)/(x-4)=(x-7)/(x-6)-(x-9)/(x-8)化简得【(x-3)(x-4)-(x-5)/(x-2)】/【(x-2)(x-4)】=【(x-7)(x-8
再问:额、不懂再答: 再答:后面的看做一个整体再问:好的吧、谢谢大神再答:回来的话,请采纳再问:啊、突然明白了呢。。。
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583
X(1+2+3+4+5+6+7+8+9+10+11)=1980,X66=1980等于30
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊
x*2x=4x4x*3x=11x11x*4x=26x26x*5x=57x57x*6x=120x120x*7x=247x247x*8x=502x502x*9x=1013x=3039x=3
通分得[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),
设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=
(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(
(x+2)/(x+3)-(x+1)/(x+2)=(x+8)/(x+9)-(x+7)/(x+8)(x+2)²/[(x+2)(x+3)]-(x+1)(x+3)/[(x+2)(x+3)]=(x+8
1.9/x+x=6,x^2+9=6x,x^2-6x+9=0,(x-3)^2=0,x=3.2.(x+1)/x+2x/(x+1)=3两边同乘以x(x+1)2x^2+(x+1)^2=3*x*(x+1)2x^
X^2+X-7=0X1=根29-1X2=-1-根29X^2+X-2=0X1=-2X2=19-6X+X^2+X=9X^2-5X=0X(X-5)=0X1=0X2=5
2x/x^2-9=x-1/x^2-6x+9-1/x+32x/(x+3)(x-3)=(x-1)/(x-3)²-1/(x+3)两边同乘以(x-3)²(x+3)2x(x-3)=(x-1)
解方程:(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开:X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得:12x=18则x=18/12=3/2