四x的三次方减去括号里负六x的三次方括号外加上括号里负九x的三次方括号外等于几
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 20:22:24
你合并完同类项会发现,只有x四方和x二方,计算出的值与x正负无关
6(x-y)^3+15(y-x)^2-9(y-x)^3=6(x-y)^3+15(x-y)^2+9(x-y)^3=15(x-y)^3+15(x-y)^2=15(x-y+1)(x-y)^2
x³-3x²+4=(x-2)²×(x+1)再问:可以告诉我过程吗再答:(x3-2x2)-(x2-4)=x2(x-2)-(x+2)(x-2)=(x22-x-2)(x-2)=
x^3-3x^2-9x-10=0设y=f(x)=x^3-3x^2-9x-10y'=3x^2-6x-9=3(x-3)(x+1)令y'=0,则x=-1或3所以x∈(-∞,-1),(3,+∞)时,y增;x∈
x^3-8x^2+19x-12=0(x^3-x)-(8x^2-20x+12)=0x(x^2-1)-4(2x^2-5x+3)=0x(x+1)(x-1)-4(x-1)(2x-3)=0(x-1)(x^2+x
x的4次方减去x的三次方加上x的平方减去x加上1等于0,用数学的语言就是x^4-x^3+x^2-x+1=0.对吗?再问:对的再答:因为x≠±1,所以原式无有理一次因式;用待定系数法(x^2+ax+1)
(a-b)(a平方+ab+b平方).
原式=4(x-y)^3*(-1/8)(x-y)^6=-(1/2)(x-y)^9
7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3,其中x=-2010.y=2012=(7x^3+3x^3-10x^3)+(6x^3y-6x^3y)+(3x^2y-3x^2
(-3)^3-(-3)+1-(-3)^2=-27+3+1-9=-32
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x^3-y^3=x^3-x^2y+y^2x-yx^2+xy^2-y^3=x^2(x-y)+xy(y-x)+y^2(x-y)=(x-y)(x^2-xy+y^2)
X^4-X^3+X^2-X=0提公因式得X^3(X-1)+X(X-1)=0(X-1)(X^3+X)=0(X-1)(X^2+1)X=0X^2+1为正数,不可能为0,故只有(X-1)X=0方程的根为1和0
(6x^4-8x^3)/(-2x^2)=6x^4/(-2x^2)-8x^3/(-2x^2)=-3x^2+4x再问:确定吗?
x^3-3x^2=x^2(x-3)
这是一个数学表达式啊!你要问什么啊?
x^3-5x^2+4x-9=x^3-(5x^2-4x)-9
再答:,,,等等,好像哪里不对,,再答:,,,,没有是,对的,,
(x+y)^3-x^3-y^3+3xy=(x+y)^3-(x+y)(x²-xy+y²)+3xy=(x+y)(x²+2xy+y²-x²+xy-y
x^3-2x^2+1=0(x-1)(x^2-x-1)=0x-1=0即x=1或x^2-x-1=0x^2-x-1=0(x-1/2)^2=5/4x-1/2=±√5/2x=(1+√5)/2或x=(1-√5)/