5x2 6xy-y2因式分解
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![5x2 6xy-y2因式分解](/uploads/image/f/352415-47-5.jpg?t=5x2+6xy-y2%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3)
(x2+2x+1)-y2,=(x+1)2-y2,=(x+y+1)(x-y+1).
2x"+xy-y"-5x+4y-3=2x"+2xy-xy-y"-6x+x+y+3y-3=2x(x+y)-y(x+y)+(x+y)-6x+3y-3=(x+y)(2x-y+1)-3(2x-y+1)=(x+
1.x^3-5x+4=x^3-x^2+x^2-x-4x+4=(x-1)(x^2+x-4)2(y^2-3y-2)(y^2-3y+4)-16=(y^2-3y)^2+2(y^2-3y)-24=(y^2-3y
(y²-1)²-6(y2-1)+9=(y²-1-3)²=(y²-4)²=(y+2)²(y-2)²
x^2+xy-2y^2-x+7y-6=(x+2y)(x-y)-x+7y-6x+2y-3Xx-y2十字相乘得:2(x+2y)-3(x-y)=-x+7y是一次项所以原式=(x+2y-3)(x-y+2)
原式=1-(x2-4xy+4y2)=1-(x-2y)2=(1+x-2y)(1-x+2y).故答案为(1+x-2y)(1-x+2y).
9x2-y2-4y-4,=9x2-(y2+4y+4),=9x2-(y+2)2,=(3x+y+2)(3x-y-2).
十字相乘法原式=(2x-3y)(x+y)
-3x2+6xy-3y2=-(3x2-6xy+3y2)=-3(x2-2xy+y2)=-3(x-y)2,故答案为:-3(x-y)2.
原式=(x2-2xy+y2)-z2=(x-y)2-z2=(x-y+z)(x-y-z).
(x2+8x+16)-16y2=(x+4)^2-(4y)^2=(x+4+4y)(x+4-4y)
x3+(y-1)x2-2xy-y2=x^3+x^2y-x^2-2xy-y^2=x^2(x+y)-(x+y)^2=(x+y)(x^2-x-y)
x2y2+3xy+2=(xy)^2+3xy+2=(xy+2)(xy+1)很高兴能帮助您~!
很难,因为不能变成系数为整数甚至分数的因式积.
=[x+(3-√5)/2*y][x-(3-√5)/2*y]有点牵强,但这是唯一的答案了
∵x2-y2=(x+y)(x-y),∴可设x2-y2+mx+5y-6=(x+y+a)(x-y+b).∵(x+y+a)(x-y+b)=x2-xy+bx+xy-y2+by+ax-ay+ab=x2-y2+(
题目可能是2x2-3xy+y2+5x-y-12吧!2x2-3xy+y2+5x-y-12=(2x-y-3)(x-y+4)
2x²+xy-3y²+x+4y-1=2×x×x+x×y-3×y×y+x+4×y-1=x×2x+x×y-y×3y+x×1+y×4-1=x×(2x+y+1)-y×(3y+4)-1再问:
首先,X^2-XY+2Y^2=(X-2Y)(X+Y)所以,设x^2-xy-2y^2-x+5y-2可分解成(X-2Y+A)(X+Y+B)则展开有X的一次项=A+B=-1Y的一次项有A-2B=5连列成方程
1.原式=(x+1)^2-y^2=(x+1+y)(x+1-y)2.公因式为(x-2)3.原式=16-(16x^2-8xy+y^2)=16-(4x-y)^2=(4+4x+y)(4-4x+y)或(-4+4