1-[3y-6] 10,[y-1=[4x 9] 20-1dejie

原式=-2x+x^2-3-x^2+2x-1=-4原式=(y+2)(y-2)/(y-3)(y+2)+(y+2)/(y+1)=(y-2)/(y-3)+(y+2)/(y+1)=(y^2-y-2+y^2-y-

(x+y)/6+(x-y)/10=3①(x+y)/6+(y-x)/10=-1②①可变为：(x+y)/6-（y-x)/10=3③②+③=(x+y)/3=2得x+y=6④②-③=（y-x）/5=-4得y-

是否代人检验了?第二步建议应先化为有括号的：3(3y-1)-12=2(5y-7)解得y=-1解题时,建议应按步骤有序的完成,养成良好的习惯.再问：我是知道错了，但我主要要的是过程，看我是错在哪？再答：

1-6y+y²=9-6y+y²-8=3²-6y+y²-8=(3-y)²-8再问：“9和8”是哪里来的？再答：把1拆开来写，因为9-8=1，这样式子9-

∵3y^2-(2y+1)(y-2)=(y-5)(y-1)==>3y^2-2y^2+3y+2=y^2-6y+5==>9y==3==>y=1/3∴原方程的解是y=1/3.

很多数学符号,还是写出来方便.

这个是Y=2吧

3y³-2y²+18-3y³+12y-2y²-2=0y²-3y-4=0(y-4)(y+1)=0y=4,y=-1

x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y=x^2-y^2+x^2-2xy+y^2-3x^2+xy=-x^2-xy=-(-2)^2-(-2)(1/3)=-4+2/3=-10/

①－②可得：x-y/10－y-x/10=4x-y／5＝4x-y＝20——③①＋②可得：x+y/3=2x+y=6——④由③④可得：x=13,y=－7

7y(x-3y)²-2(3y-x)³=7y(x-3y)²+2(x-3y)³=(x-3y)²[7y+2(x-3y)=(x-3y)²(7y+2X

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

[1]y+2分之y的平方-6y+9除以[3-y]=（3-y)²/(y+2)×/(3-y)=(3-y)/(y+2)[2]x的立方分之x的平方y乘以[-y分之1]=x²y/x³

第一项与第三项先合并9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y^2*(x-y)(x+1)=(x-y)(x+1)(9xy+6y^2)-3y(x-y)(3x+2y)=(x-y)(x+1

1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)

∵3y^2-(2y+1)(y-2)=(y-5)(y-1)==>3y^2-2y^2+3y+2=y^2-6y+5==>9y==3==>y=1/3∴原方程的解是y=1/3.希望对你有所帮助,

(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.-(10x+1/90y)=x+y-2x-1/2y--3x-1/6y-4x-1/12y-5x-1/20y

题目有误（1）若是(3y+5)/(3y-6)=1/2+(5y-4)/(2y-4),(3y+5)/(3y-6)=1/2+(5y-4)/(2y-4)两边同时乘以12(y-2),得(3y+5)x4=12(y

完整设1/(x+y)=a,1/(x-y)=b原方程组可变为4a+6b=39b-a=1a=9b-136b-4+6b=3b=1/6,a=1/2x+y=2x-y=6所以原方程组的解为：x=4,y=-2