已知向量a (cosx,-根号3 2),向量b=sin,cos2x
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![已知向量a (cosx,-根号3 2),向量b=sin,cos2x](/uploads/image/f/4253449-49-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fa+%28cosx%2C-%E6%A0%B9%E5%8F%B73+2%29%2C%E5%90%91%E9%87%8Fb%3Dsin%2Ccos2x)
(1)F(x)=2(cosx)^2-2√3cosxsinx=cos2x-√3sin2x+1=2sin(2x-π/6)+1最小正周期T=π函数f(x)在【0,π】上的单调递增区间为[0,π/3]∪[5π
f(x)=向量a乘向量b=2sinx*√3cosx+(√2cosx+1)(√2cosx-1)=√3sin2x+2(cosx)²-1=√3sin2x+cos2x=2sin(2x+π/6)∴T=
已知函数f(x)=向量a*向量b,其中向量a=(2cosx,根号3sinx),向量b=(cosx,-2cosx)(1)求函数f(x)在[0,π]上的单调递增区间和最小值(2)在三角形ABC中,a、b、
f(x)=2[√3cosxsinx+2(cosx)^2]-2[(sinx)^2+(2cosx)^2]-1=√3sin2x-2(cosx)^2-3=√3sin2x-cos2x-4=2sin(2x-π/6
f(x)=a.b=sinxcosx+√3cosx^2=1/2sin2x+√3(cos2x+1)/2=sin(2x+π/3)+√3/2(1)递增区间:-π/2+2kπ
向量a=(sinx,根号3cosx),向量b=(cosx,cosx),f(x)=向量a*向量b=sinxcosx+√3cos²x=1/2sin2x+√3/2(1+cos2x)=1/2sin2
f(x)=5根号3*sinxcosx+2(cosx)²+(sinx)²+4(cosx)²=5根号3sinxcosx+5(cosx)²+1=5*根号3/2*sin
题目写得应该稍有问题,我想应该是:函数f(x)=2*a点乘b+(2m-1)要不然f(x)也是个向量.1)f(x)=2(isqrt(3)sinx+jcosx).(icosx+jcosx)+2m-1=2s
f(x)=mn=2cos^2x+2√3sinxcosx+a-1+1=cos2x+√3sin2x+a+1=2sin(2x+π/6)+a+1f(x)=0sin(2x+π/6)=(-a-1)/2f(x)在【
1a·b=√3sinxcosx+cosx^2=√3sin(2x)/2+(1+cos(2x))/2=sin(2x+π/6)+1/2故:f(x)=a·b-1/2=sin(2x+π/6)最小正周期:T=2π
向量a.向量b=√3sinxcosx+cos^2x-m^2.=2[(√3/2)sin2x+(1+cos2x)/2-m^2.(1)f(x)=sin(2x+π/6)+1/2-m^2.再问:还有第二问呢?再
(1)向量a=(2cosx,根号3),b=(cosx,-sinx)a∥b,所以%D¢cosx/cosx=√3/(-sinx)%D%A即%D%Asinx=-√3/2%D%A所以%D¢
f(x)=2sinxcosx+2√3(cosx)^2-1-√3=sin2x+√3cos2x-1=2sin(2x+π/3)-1(1)当2x+π/3=π/2,即x=π/12时,f(x)取得最大值f(π/1
f(x)=2cos²x+2√3sinxcosx=cos2x+1+√3sin2x=2sin(2x+π/6)+1(1)T=2π/2=π(2)当x∈[π/24,5π/24]时,2x+π/6∈[π/
(1)f(x)=cos²x+√3sinxcosx=(1+cos2x)/2+√3/2sin2x=√3/2sin2x+1/2cos2x+1/2=sin(2x+π/6)+(1/2)最小正周期为π(
1.f(x)=2(√3sinxcosx+(cosx)^2)+2m-1=√3sin2x+cos2x+2m=2sin(2x+pi/6)+2m最小正周期=pi2.x属于[0,pi/2]f(x)最小值=2si
(1)解析:函数f(x)=√3cos²x+sinxcosx=√3(cos2x+1)/2+1/2sin2x=sin(2x+π/6)+√3则函数的最小正周期为π,图像的对称轴方程x=kπ+π/6
紧跟题意1、f(x)=a*b=-cos^2x+sinx*根号3*cosx=sin(2x-π/6)-1/22、T=2π/2=π,-π/2+2kπ《2x-π/6《π/2+2kπ,解得kπ-π/6《x《π/
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(1)向量a=(2cosx,根号3),b=(cosx,-sinx)a∥b,所以2cosx/cosx=√3/(-sinx)即sinx=-√3/2所以2cos²x-sinx=2(1-sin