C语言怎样随机产生5*5的矩阵

#include#includevoidRAND_RECTANGE(intx);intmain(void){intx;srand(time(0));x=rand()%10;RAND_RECTANGE(

#include<stdio.h>#include<stdlib.h>#defineM10#defineN10intmain(void){inti=0,j=0;intArr[M

刚答过一个#include#include#include#includeintmain(){charr[7];inti,j,k,t,f;FILE*fp;fp=fopen("d:\\file

#include#include#includeusingnamespacestd;intmain(){intha=0;inthb=0;intn;cin>>n;srand((int)time(0));

错了,没写路线,重改了一下：#include#include#include#include#definerandomize()srand((unsigned)time(NULL))intM[10][

#include#include#include#includeintmain(){\x05\x05charr[7];\x05inti,j,k,t,f;\x05srand(time(0));\x05f

#includeintmain(){\x05inta[5][5]={{1,2,3,4,5},{1,2,3,4,5},{5,4,3,2,1},{1,3,4,2,5},{5,4,3,2,1}};\x05i

#include#defineSIZE5*5intmain(){\x09inta[SIZE],i;\x09for(i=0;i

#include <stdio.h>#include <stdlib.h>#include <time.h>int mks(

#include#include#include#defineN1000intfun(inta[],intnum);voidmain(){inti,a[N],b,num,n;printf("\n请输入

一个两重循环搞定,随机数的函数是rand(),一个例子：/*产生介于1到10间的随机数值,此范例未设随机数种子,完整的随机数产生请参考srand（）*/#includemain(){inti,j;fo

Dima%(1To6,1To6),b%(1To6,1To6)PrivateSubCommand1_Click()Fori=1To5Forj=1To5a(i,j)=Int(Rnd*90+10)Pictu

ound(rand([1020])*7)+3%不需要整数的话,把round去掉就行了

您这代码b=rand()%((int)(100/b))+1;有问题,b不能被产生出来,因为b根本还没确定是多少,就被用去100/b了下面的代码可以产生两个能整除的数：#include#includem

每一行中的A（i）必须排在对应的B（i）之前这一句是什么意思?

若要放进5*6的矩阵中A,T=rand(5,6);A=T;

for(i=1;i

//---------------------------------------------------------------------------#include<stdio.h>

输出结果哪里不对可以说下不?再问：有发代码的图片，有看见么？如果看不见的话，请看私信……拜托了~再答：#include"stdio.h"#include"time.h"#include"stdlib.

用srand和rand函数：举例：#include#include#includeintmain(){inta[10][2];inti,j,x,y;srand(time(NULL));/*随机数种子*