求y=2x与y=3-x^3围成的面积怎么理解上下都有面积
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|3x-2y-3|+(7x+3y-53)=03x-2y-3=07x+3y-53=0x=5y=6满意请采纳
(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)²*(x-y)=(2x+y)/(x-y)x-3y=0,x=3y(2x+y)/(x-y)=(6y+y)/(3y-y
绝对值和平方都是正的所以2x+y-1,3x-2y-5都为0解方程组3x-2y-5=02x+y-=0解得x=1然后将起带入2x+y=0得y=-1
按题意得:|x-4y-2|=0;(2x+3y+7)的平方=0解得下x=6;y=1
3y=x+4两边同乘以2,得:6y=2x+8所以2x=6y-82x+5y=-19把2x=6y-8代入得:6y-8+5y=-1911y=-11所以y=-1把y=-1代入2x=6y-8得:2x=-6-8x
Ix-7I=0x=7;I3x+2y-25I=0,3x+2y-25=0把x=7代入得,21+2y-25=0y=2
3x=8yx/y=8/3(1)x+y/y=x/y+1=8/3+1=11/3(2)2x+3y/x-2y分子分母同时除以y得=(2x/y+3)/(x/y-2)=(16/3+3)/(8/3-2)=(25/3
根据方程式可以得出方程组:3x+2y=175x-y=-2解此方程得:x=1y=7解方程不用我说了吧,2式乘2再加上1式可以解出x
|2x+y-1|+(3x-2y-5)的平方=0非负数的性质:几个非负数的和为0,每个非负数都等于0.所以2x+y=1,3x-2y=5解得:x=1,y=-1
y-2=kxx=3,y=1得出k=-1/3y=-1/3x+2
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)÷2y=(x+y)(x-y)-y^2+(x-y)^2-2y(3x^2-xy)÷2y=(x+y)(x-y)-y^2+(x-y)^2
y'=(cos²x)'-(sin3^x)'=2cosx·(cosx)'-cos3^x·(3^x)'=2cosx·(-sinx)-cos3^x·(3^x·ln3)=-sin2x-ln3·cos
x/2+y/3=-3方程两边同时乘以24得:12x+8y=-727x=8y-4可得8y=7x+4代入上式得12x+7x+4=-7219x+4=-72x=-4
设y=k/x^2将x=3,y=4代入得k=36这也算与x的函数
两个都是非负数相加为0则都等于0所以x-4y-2=02x+3y+7=0y=-1,x=-2
x=-y3x-2y=-10解方程式得5x=-10x=-2y=2
(x-2y)/(x+2y)=3取倒数(x+2y)/(x-2y)=1/3所以原式=(1/3)[(x-2y)/(x+2y)]-3[(x+2y)/(x-2y)]=(1/3)×3-3×(1/3)=0
原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009)y=0+(1×1004-2009)y=-1005y=1005/2