求和S=1! 3! 5! C语言程序.-搜答案-百度作业网

#include"stdio.h"voidfun(intn,intk){intj;doublesum=0;for(j=1;j

voidmain(){intnum=1;intresult=0;for(num=1;num

楼上两位的代码可能有点小问题s += m*m+1/m;改成s += m*m+1.0/m;再问：您好，请您帮忙写一个完整的编程好么？谢谢了再答：#include&

没得错误,main函数前面加void就好了

//VC6.0编译运行通过//求和s=1!+3!+5!#include//求阶乘函数intf(intn){if(1==n){return1;}returnf(n-1)*n;}//main函数intma

#include<stdio.h>#define maxn 101main(){ int i, sum

整型相除结果还是整型.1/1=11/2=01/3=0...所以结果永远是1把t=1/i改成t=1.0/i就可以了.

其实这个题目根本不用求出S,也不用担心它会超出int范围.因为是数列,所以就要从数列规律上去找结果.比如a=1,n=5,s=3.列竖式111111111111111------12345后3位是345

/*求任意两个整数m,n之间自然数之和*/#includevoidmain(){inti=0;longsum=0;while(i

你好! hehe的函数内容改了,你对照原来的程序看看吧,满意请采纳#include<stdio.h>#include<math.h>

#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i

#include#includeintSum(intn){inti,s=0;for(i=1;i

#includevoidmain(){intn,t=1,s=0;for(n=1;n

#includeintmain(void){inti=1,s=0;while(i

#include <stdio.h>int main(){int a,b;scanf("%d%d",&a,&b);prin

#include<stdio.h>main(){\x09int a,b,c,s=0;\x09for(a=1;a<=10;a++)\x09{\x09 &

#include<stdio.h>void main(){\x09int i, n, sum = 0;\x09int

#include <stdio.h>void main(){ int n;//n没声明int i=1,sum;sum=0;//sum没初始

#includeintmain(){inti,s=0;for(i=1;i

#includeintmain(){inti,s=0;for(i=1;i