用vb.随机产生10个[10,100]的整数,求该组数的最大值.最小值及其位置

Dima%(1To20)Fori=1To20a(i)=Int(Rnd*90+10)Printa(i);NextPrintFori=1To20Ifa(i)Mod2=1ThenPrinta(i);EndI

窗体中加命令按钮,单击事件代码如下：PrivateSubCommand1_Click()  Randomize  Dima(1To20)AsInteger&nb

PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(

DimnMaxasInteger,nMinasInteger,nTmpasInteger,nJsqasIntegerDimdSumasDoubleRandomizenTmp=CInt(Rnd*100)

PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima

command1完成第一题,command2完成第二题PrivateSubCommand1_Click()Dimx%(1To10),n%,i%n=1DoWhilen

Dima(9)AsIntegerRandomizea(0)=Int(Rnd()*21+10)Doa(1)=Int(Rnd()*21+10)LoopWhilea(1)=a(0)Doa(2)=Int(Rn

Public Function IsPrime(ByVal x As Integer) As Boolean  

Dima(10)Fori=0To9a(i)=Int(100+100*Rnd)NextiFori=0To8Forj=iTo9Ifa(i)t=a(i)a(i)=a(j)a(j)=tEndIfNextjNe

我已经上机验证过了,正确.思路：产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s

Dimy%,x%Fori=1To10x=Int(Rnd*100)'[0,99]Printx;Ifi=1Theny=xElseIfy>xTheny=xEndIfNextiPrint"最小值";x如果是N

OptionBase1Dima(20)PrivateSubForm_Load()RandomizeFori=1To10a(i)=Int(10+90*Rnd)NextEndSubPrivateSubCo

PrivateSubForm_click()DimA(1To10)RandomizeForI=1To10A(I)=Int(Rnd*90)+10NextIForI=1To9'选择法p=IForJ=I+1

subform_click()dima%(20)fori=1to20a(i)=int(rnd()*10+1)printa(i),nextendsu

'试一下：PrivateSubCommand1_Click()Dima(1To10)AsStringDimiAsInteger,jAsIntegerFori=1To10Randomizea(i)=Ch

Dima(10)AsIntegerDimi%,j%,t%RandomizFori=1To10a(i)=Int(Rnd*90+10)Printa(i);NextPrintFori=1To9Forj=i+

DimMyValue(10)AsIntegerDimi,j,pAsIntegerFori=0To9RandomizeMyValue(i)=Int((100*Rnd)+1)NextFori=0To9Fo

是“奇数”吗..?另外一共就产生十个,每行显示十个……是不是产生任意多个,然后每行输出十个?奇数的话范围就在11~99之间,用2n+1法产生奇数的话n的取值范围就是5~49新建工程,窗体上放个文本框,

vb6测试通过PrivateSubCommand1_Click()Dima(10)AsInteger,tempAsInteger,iAsInteger,jAsIntegerRandomizetemp=

Option ExplicitPrivate Sub Form_Load()RandomizeMe.AutoRedraw = TrueDim