用递归的方法编写一个返回长整形函数,计算斐波那契数列的前20项
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![用递归的方法编写一个返回长整形函数,计算斐波那契数列的前20项](/uploads/image/f/6296008-40-8.jpg?t=%E7%94%A8%E9%80%92%E5%BD%92%E7%9A%84%E6%96%B9%E6%B3%95%E7%BC%96%E5%86%99%E4%B8%80%E4%B8%AA%E8%BF%94%E5%9B%9E%E9%95%BF%E6%95%B4%E5%BD%A2%E5%87%BD%E6%95%B0%2C%E8%AE%A1%E7%AE%97%E6%96%90%E6%B3%A2%E9%82%A3%E5%A5%91%E6%95%B0%E5%88%97%E7%9A%84%E5%89%8D20%E9%A1%B9)
#includeintdigit(intn,intk){returnk>1digit(n/10,k-1):n%10;}intmain(){printf("%d",digit(12345,3));}
#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i
添加一个文本框输入前N项的N值,再添加一个命令按钮即可PrivateFunctionF(NAsLong)AsLongIfN>2ThenF=F(N-1)+F(N-2)ElseF=1EndIfEndFun
PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli
#includelongintf(intn){if(n==0)return0;elseif(n==1)return1;elsereturnf(n-1)+f(n-2);}intmain
// C++int F(int n) {if (n == 0) return 1;else if
longadd(intn){intt=n-1;if(t>1){longresult=n*t;longsum=result+add(t);returnsum;}else{returnn;}}楼上的方法,
cludestdio.hvoidmain(){intmax_4(inta,intb,intc,intd);inta,b,c,d,max;printf("Pleaseenterintergernumbe
#includeintFibonacci(intn){if(n==1||n==2)//递归结束的条件,求前两项return1;elsereturnFibonacci(n-1)+Fibonacci(n-
代码如下:OptionExplicitPrivateSubCommand1_Click()MsgBoxP(2,2)EndSubFunctionP(ByValnAsInteger,ByValxAsDou
longfac(int);这一步应该为longfac(int,float);y=fac(n);这一步应该为:y=fac(n,x);elseif(n=0)f=1;这一步应该为:elseif(n==0)f
#include <stdio.h>char* dg(char* instr, char* outstr, char* 
#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\
#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-
functiongqj=erfen(p,a,b,e)ifabs(b-a)
与其问人哪比得上自己在编译器里试试
1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n
#includeintfibo(intn){if(nreturn1;elsereturnfibo(n-1)+fibo(n-2);}intmain(){intn;scanf("%d",&n);print
你的题目应该是:如何定义一个函数,求一个整形数组的最大元素,并编写主函数吧.#include#include#include#includeintmax(intarr[],intlen){//retu
//fibonacci数列:11235813213455...#includedoublefib_val[100]={0};doublefibonacci_1(intn)//递归,计算时间长,n最好不