编写调用函数求三角形面积

#include#includefloatarea(float,float,float);voidmain(){\x09floata,b,c,result;\x09printf("输入三角形的三边:\

main(){ints;s=getfactorial(6)+getfactorial(10)+getfactorial(20)printf("s=%d",s);}intgetfactorial(int

#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s

PrivateFunctionSUM(Fir_LAsDouble,Fir_SAsDouble,Scend_LAsDouble,Scend_SAsDouble)AsDoubleSUM=Fir_L*Fir

intjc(intx){returnx==1?1:jc(x-1)*x;}再问：可以编一个完整的么？我直接运行试一下。。。新手，不好意思，，，，谢谢再答：intjc(intx){returnx==1?1

上面是对的,f1是求体积的,f2是求表面积的.

#includeusingnamespacestd;floatmianji(floata,floatb){returna*b;}floatzhouchang(floata,floatb){return

#include<stdio.h>#include<stdlib.h>#define Pi 3.14159double square(double

#include<stdio.h>#define Pi 3.14159double Square(double r){  &nb

#include#includeusingnamespacestd;intmain(){floata;floatb;floatc;floats;floatp;coutb>>c;p=(a+b

首先你那个a[i]=a[i]*(n-j)/j公式有点问题吧,这样会输出全是1的啊...如果还是按照你这样可以改成如下代码：#include"stdafx.h"#include#include#incl

#include#defineN9voidmain(){inti,j,a[N][N]={0};for(i=1;i

#includemain(){longintn,i,j,k;doublem;printf("请输入数字'n':");scanf("%d",&n);if(n%2==1){for（i=0;i0){for（

p=1/4*(2*x*z+y*y-x*x-z*z);应该改为p=1.0/4*(2*x*z+y*y-x*x-z*z);或者p=1/4.0*(2*x*z+y*y-x*x-z*z);原因是：当进行运算时,1

#include#includevoidb1(){floatl,s,k;inta,b,c,h;printf("\n");printf("\n");printf("输入a,b,c的值\n");print

PublicFunctiontrangle(aAsDouble,bAsDouble,cAsDouble)AsDoubleIfa+bDimsAsDoubles=0.5*(a+b+c)a=s-ab=s-b

voids(folata,folatb,folatc){folatp;p=(a+b+c)/2;S=√[p(p-a)(p-b)(p-c)];returns;}

functionfun(d,h){if(d

%调用函数function[AL]=triangle(a,b,c)%A为三角形面积,L为三角形周长,a,b,c分别为三角形三条边L=a+b+c;d=L/2;%计算面积时用到的中间变量A=sqr(d*(

利用海伦公式：S=(p(p-a)(p-b)(p-c))^(1/2);S为三角形面积,a,b,c为三角形三边长,p为三角形半周长（p=（a+b+c)*(1/2))(p(p-a)(p-b)(p-c))^(