若x-y=5,xy=2,则x² y²=-搜答案-百度作业网

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xy/(x+y)=2解得xy=2(x+y)所以(3x-5xy+3y)/(-x+3xy-y)=(3/2*xy-5xy)/(-1/2*xy+3xy)=-7/5

x^2y+xy^2=xy(x+y)=1/5

1/x+1/y=2y+x=2xy(2x-xy+2y)=2(x+y)-xy=3xy(3x+5xy+3y)=3(x+y)+5xy=11xy(2x-xy+2y)÷(3x+5xy+3y)=3xy/11xy=3

x²+y²=(x+y)²-2xy=10²+2=102

x=-1,y=-6或x=6,y=1代入式子得x^2-xy^2=37或30x^2y+xy^2=-42或42

x²y+xy²=xy(x+y)=10

x^2y+xy^2=xy(x+y)=(-3)×5=-15

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

第1小题：x²y-xy²=xy(x-y)=6(5)=30第2小题：(x+y)²=x²+y²+2xy=x²+y²-2xy+4xy=(

2x^3-7x^y+5xy^2+14y^3=3(x^3-3x^2y+2xy^2+3y^3)-(x^3-2x^2y+xy^2-5y^3)=3m-n

=(x^4+x^3y)+(y^4+xy^3)+(4x^3y+4x^2y^2)+(4xy^3+4x^2y^2)+x^2y+xy^2=x^3(x+y)+y^3(x+y)+4x^2y(y+x)+4xy^2(

因为xy/（x+y）=1/2所以x+y=2xy原式=3（x+y)-5xy/(-x-y+3xy)=3*2xy-5xy/(-2xy+3xy)=xy/xy=1

xy/(x+y)=2(x+y)/xy=1/21/x+1/y=1/2(3x-xy+3y)/(-x+3xy-y)=(3/y-1+3/x)/(-1/y+3-1/x)=[3(1/x+1/y)-1]/[(3-(

1/x-1/y=5即,(y-x)/xy=5即,x-y=-5xy(3x-2xy-3y)/(x+xy-y)=[3(x-y)-2xy]/[(x-y)+xy]=(-15xy-2xy)/(-5xy+xy)=(-

解x²y-xy²=xy(x-y)=5×1=5a²b+ab²=1∴ab(a+b)=1∵a+b=3∴3ab=1∴ab=1/3再问：a(a-b)-a+b=?再答：=a

(2x+2y-3xy)/(2xy+x+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(10xy-3xy)/(5xy+2xy)=7xy/7xy=1如果本题有什么不明白可以追问,

x+y=5xy（2x-3xy+2y)/(x+2xy+y）=[2（x+y）-3xy]/[(x+y)+2xy]=(2×5xy-3xy)/(5xy+2xy)=7xy/7xy=1再问：若x＋1/x＝3,求(x

x^2y+xy^2＝xy×（x+y）＝6×5＝30

由x,y为正得x=y/(y-1)>0、y=x/(x-1)>0,所以x>1、y>1,因此x+2y=y/(y-1)+2y=（y-1+1)/(y-1)+2(y-1+1)=3+1/(y-1)+2(y-1)>=