苯甲醇与乙酸反应的化学方程式-搜答案-百度作业网

乙酸钠不会和乙醇反应.CH3COONa+H2SO4-----CH3COOH+NaHSO4

2CH3COOH+Fe====Fe(CH3COO)2+H22CH3COOH+CaCO3====Ca(2CH3COO)2+CO2+H2OCH3COOH+H3CHO====CH3COOCH3+H2OHCO

2CH3OH(g)＝CH3OCH3(g)＋H2O(g)

酯化反应O‖CF3COOH+CH3OH→CF3C-O-CH3+H2O在催化剂并加热条件下

CH3-CH(OH)-COOH+CH3COOH==浓硫酸,加热,可逆==CH3-COO-CH(CH3)-COOH+H2OCH3-CH(OH)-COOH+CH3COOH==浓硫酸,加热,可逆==CH3-

脂化反应酸和醇反应生成脂,这个也就是为什么喝醋可以解酒的道理.

CaCO3+2CH3COOH=(CH3COO)2Ca+CO2+H2ONaOH+CH3COOH=CH3COONa+H2O

CH3CH2OH+CH3COOH=CH3COOCH2CH3+H2O(条件是加热,浓硫酸,可逆符号)补充：在常温下,不反应.要在浓硫酸做催化剂,加热的情况才会反应.

HOCH2-C6H4-COOH+CH3CH2OH--（浓硫酸,△）-->HOCH2-C6H4-COOCH2CH3+H2OHOCH2-C6H4-COOH+CH3COOH--（浓硫酸,△）-->CH3CO

Na2C2+2CH3COOH=2CH3COONa+C2H2可以看成是复分解,大多数有酸参加的反应你不会写的时候就看成是复分解

CH3COOH+CH3OH==浓硫酸,加热==CH3COOCH3+H2O

Na+ 在中性或 HAc 酸性溶液中与乙酸铀酰锌Zn(CH3COO)2 · UO2(CH3COO)2 生成柠檬黄色结晶性沉淀得到沉淀,用于分

CH3CH=CH2OH+CH3COOH=H2O+CH3CH=CH2OCOCH3

酸性环境下KMnO4的氧化性最强.甲醇可以被酸性高锰酸钾氧化,得到的产物是甲醛：5CH3OH+2KMnO4+3H2SO4==2MnSO4+5CH2O+K2SO4+8H2O

2CH3COOH+2Na=2CH3COONa+H2↑

CH3COOH＋CH3OH→CH3COOCH3+H2O

化学方程式CH3COOH+NaHCO3====CH3COONa+H2O+CO2↑当然我们也习惯性地写成HAc+NaHCO3====NaAc+↑CO2+H2O离子方程式HAc+HCO3-===Ac-+H

CH3-CH(OH)-COOH+CH3COOH==浓硫酸,加热,可逆==CH3-COO-CH(CH3)-COOH+H2O

CH3COOH+NaOH=CH3COONa+H2O