设y=In2x sin3x则dz=
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![设y=In2x sin3x则dz=](/uploads/image/f/7253220-12-0.jpg?t=%E8%AE%BEy%3DIn2x+sin3x%E5%88%99dz%3D)
∂z/∂x=2xy∂z/∂u=x²所以dz=2xydx+x²dy
可以使用全微分公式求解,对方程分别对x,y求偏导,可得:偏Z偏X=1/(e^yz-1);偏Z偏Y=[z(e^yz)-z-x]/[y-y(e^yz)];dz=(偏z偏x)dx+(偏z偏y)dy;电脑不好
dz=2x+y就是对z求x的导数吧
z'x=2e^(2x+y)z'y=e^(2x+y)所以dz=2e^(2x+y)dx+e^(2x+y)dy
z=(x+y)^2*cos(x^2*y^2)dz/dx=2*(x+y)*cos(x^2*y^2)-2*(x+y)^2*sin(x^2*y^2)*x*y^2dz/dy=2*(x+y)*cos(x^2*y
再问:非常感谢,还要问大侠一道题面目。曲线y=x³+3x的拐点坐标为???再答:y'=3x²+3y''=3x令y"=0,得x=3当x=3时,y=36所以拐点坐标(3,36)
∂z/∂x=2x/(1+x^2+y^2)∂z/∂y=2y/(1+x^2+y^2)dz=∂z/∂xdx+∂z/W
z=y*cos(x+y)对x求偏导得y*(-sin(x+y))=-y*sin(x+y)对y求偏导得cos(x+y)+y*(-sin(x+y))=cos(x+y)-y*sin(x+y)所以dz=-y*s
dz=f'x(x/y)dx+f'y(x/y)dy=[f'(x/y)/y]dx+f'(x/y)(-x/y²)dy
z=lnx^z+lny^x=zlnx+xlnyz=xlny/(1-lnx)先关于x求偏导,把y看做常数,再对y求偏导,把x看做常数dz=0dx+x/y(1-lnx)dy(此处省略了一些计算过程,)dz
http://hi.baidu.com/fjzntlb/album/item/ef8139f61e7f7842730eec56.html#
zx=1/(1+(x/y)²)*1/y=y/(x²+y²)zy=1/(1+(x/y)²)*(-x/y²)=-x/(x²+y²)所以
f(x)=z=x+y/x-ydz=fxdx+fydy=[[(x-y)-(x+y)]/(x-y)^2]dx+[[(x-y)+(x+y)]/(x-y)^2]dy=-2y/(x-y)^2dx+2x/(x-y
dz=Z'xdx+Z'ydy=2xcos(x^2+y^2)dx+2ycos(x^2+y^2)dy
dz=[2e^(2x+y)]dx+[e^(2x+y)]dy
再问:啊不好意思搞错了。。是z=e^(x^2+y^2),求dz,谢谢你帮我解答一下吧。。再答:
zx=2xzy=3y²dz=2xdx+3y²dy再问:谢谢!再问这位大侠一题若函数u(x,y)=y/x则du|(1,1)=?注:(1,1)在|的右下角再答:ux=-y/x²
dz/dx=dz/du*(du/dx)=2u*1=2udz/dy=dz/du*(du/dy)=2u*1=2u和v没关系
u=x^2+y∂u/∂x=2x∂u/∂y=1du=(∂u/∂x)dx+(∂u/∂y)dy=2xdx+dy
dz=dx/(x+y)+dy/(x+y)