VB作业假设有1,2,3到36共36个整数.任取其中不重复的四个数
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dimnum3,num7asintegerfori=1to1000ifimod3=0thennum3=num3+1endififimod7=0thennum7=num7+1endifnext最后num
这样?Private Sub Command1_Click()Dim AA = 10'假设A变量,(8-12A)*SIN(3.4π+2)的VB
3再答:6再答:9再答:12再答:12再答:15再答:18再答:21再答:24再答:27再答:30再答:33再答:36再答:39再答:42再答:45再答:48再答:51再答:54再答:57再答:60再
你给的公式不对!应该是π/2=2^2/1*3×4^2/3*5×.×(这个公式求的精度不高!代码如下:DimPI1AsDoubleDimPI2AsDoubleDimTempAsDoubleDimnAsD
PrivateSubCommand1_Click()DimsAsString,nAsInteger,iAsIntegerFori=1To100n=n+iNextiPrint"1+2+3+……+100=
PrivateSubForm_Click()Print"10^-2=",10^-2Print"36^0.5=",36^0.5Print"8^(1/3)=",8^(1/3)'立方根Print"Sqr(4
PrivateSubCommand1_Click()DimSAsDouble,jcAsDouble,NAsIntegerjc=1N=Val(InputBox("请输入N"))Fori=1ToNjc=j
Private Sub Command1_Click() Dim a As Long &nbs
PrivateSubForm_Load()DimiAsInteger,nAsLongDimkAsLongi=1:n=1DoWhilei
s=1fori=1to10s=s*inextmsgboxs
PrivateSubCommand1_Click()DimtmpStrAsString,tmpStr1AsStringDimmpStr2AsString,tmpStr3AsStringDimaAsIn
PrivateSubCommand1_Click()DimnAsInteger,iAsInteger,jAsInteger,Sum&,m&n=Val(InputBox("请输入N值"))Sum=0Fo
法一:这个方法的思路很直接,数学味较浓.既然在VB6中没有阶乘的运算,那么我就自己造一个函数用来算一个整数的阶乘.FunctionTimeStep(NumberAsInteger)AsLongTime
DimsumAsLongDimiAsIntegerDimnAsLongn=InputBox("n=","输入")Fori=1Tonsum=sum+i^2NextiDebug.Printsum
OptionExplicitPrivateSubCommand1_Click()DimiAsIntegerDimaAsIntegerDimbAsIntegerDimcAsIntegerDimnAsIn
在vb中真命题用0表示,假命题用1表示.判断句的优先级为从左到右,2=3是一个假命题则为0,因此该命题变为0
Array函数返回一个包含数组的Variant.语法Array(arglist)所需的arglist参数是一个用逗号隔开的值表,这些值用于给Variant所包含的数组的各元素赋值.如果不提供参数,则创
mid从指定位置截取指定长度的容.mid(string,start,len)
sum定义为整型肯定会溢出的必须定义为doublePrivateSubCommandButton1_Click()DimiAsIntegerDimsumAsDoublesum=1Fori=1To100
(1)Fori=0To100Debug.PrintiNext(2)Fori=1To9Debug.Print-iNext(3)Fori=10To99Debug.PrintiNext(4)Fori=&H4