x 2分之(x-2)-1=x的平方-4分之16
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![x 2分之(x-2)-1=x的平方-4分之16](/uploads/image/f/887821-61-1.jpg?t=x+2%E5%88%86%E4%B9%8B%28x-2%29-1%3Dx%E7%9A%84%E5%B9%B3%E6%96%B9-4%E5%88%86%E4%B9%8B16)
你的题目应该是:2x/(x^2-1)=A/(x+1)+B/(x-1)对问题进行变形得:2x/[(x+1)(x-1)]=A/(x+1)+B/(x-1)对等式的右边进行通分整理得2x/[(x+1)(x-1
x+1/x=2(x+1/x)^2=4x^2+2+1/x^2=4x^2+1/x^2=2
x^2-3x+2=0(x-2)(x-1)=0x=2或x=1当x=2时x^2+1/x^2=2^2+1/2^2=4+1/4=17/4当x=1时x^2+1/x^2=1^2+1/1^2=1+1=2
X1+X2=-B/A=2X1*X2=C/A=1/2求得X1=1+根号2或者X1=1-根号2从而求出X2的值X1/X2+X2/X1=(X1*X1+X2*X2)/(X1X2)=6
=2x/(x+2)(x-2)-(x+2)/(x+2)(x-2)=[2x-(x+2)]/(x+2)(x-2)=(2-x)/(x+2)(x-2)=-1/(x+2)
两边乘以(x+3)(x-3)得12-2(x+3)=x-312-2x-6=x-3-3x=-9x=3检验:x=3是增根∴方程无解
原式=(x+1)/(x-1)-x(x-2)/(x+1)(x-1)÷(x-2)(x+1)/(x+1)²=(x+1)/(x-1)-x/(x-1)=(x+1-x)/(x-1)=1/(x-1)请好评
2(x2+x2分之1)-3(x+x分之1)-1=0解方程,是这个吧2(x2+2+x2分之1)-3(x+x分之1)-5=02(x+x分之1)平方-3(x+x分之1)-5=0[2(x+x分之1)-5][(
F(x)=2x/(1+x²)F(-x)=-2x/(1+x²)可知他是奇函数F(0)=0当x>0时F(x)=2x/(1+x²)分子分母除以x &nbs
x+1/x=10x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/[(x+1/x)^2-1]=1/(10^2-1)=1/99
x^(1/2)+x^(-1/2)=3求x^2+x^(-2)-(x^(3/2)+x^(-3/2))/2-3解:x^(1/2)+x^(-1/2)=3两边平方,得x+x^(-1)+2=9即x+x^(-1)=
x的2次方-2x分之x+2再-去x2次方-4x+4分之x-1=x(x-2)分之x+2-(x-2)²分之x-1=x(x-2)²分之(x+2)(x-2)-x(x-2)²分之x
x²+2x+1=10(x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【(x²+4)/x-4】÷【(x²-4)/(x²+2x)】=【(x&
(x^2-2x+1)/(x^2-1)+1/(x+1)=(x-1)^2/(x+1)(x-1)+1/(x+1)=(x-1)/(x+1)+1/(x+1)=x/(x+1)=1-根2分之一
发照片呀再问:请原谅手机不行再问:请帮我一下,谢谢。再答:看不明白再问:你写出来就行了的再答: 再答:是这样吗再问:嗯,麻烦把过程写详细点再答:我说题目对不再问:是的再问:对的再问:还有一个
x+2/x=c+2/c~x1=c,x2=2/c;x+2/(x-1)=a+2/(a-1);(x-1)+2/(x-1)=(a-1)+2/(a-1);x1-1=a-1;x2-1=2/(a-1);x1=a;x
x2-x+1分之x=6分之一x²-x+1=6xx²+1=7xx+1x=7(x+1/x)²=7²x²+x+1/x²=49x²+1/x
x2+2x-3分之2x+x+3分之1=14x-3分之5x+3分之1=13分之1x+3分之1=13分之1x=3分之2x=2如果有不会的追问,
这是七年级下册的分式方程.1.去分母:两边同时乘X*(X-2)得X²+4-X²=a*(X-2)2.去括号,合并同类项得aX=2a+43.系数化为一得X=a分之2a+4因为方程无解,
x1+x2=4x1x2=-1(x1+x2)^2/(1/x1+1/x2)=(x1+x2)^2*x1x2/(x1+x2)=x1x2*(x1+x2)=-4