y=3x^2-2cosx 2求导过程
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(u/v)'=(u'v-v'u)/(v^2)根据除尘公式,得:y'=[cost(3+2t)-2sint]/(3+2t)^2就这样,化简略再问:我就是做到这步就卡在那了,麻烦帮忙化简一下呗还有化简过程。
y'=2-x的-2次方×8y'=2-8x^(-2)y′=2-8/x²
y=x^(3/2)-3x^(1/2)+3x^(-1/2)求导:(3/2)x^(1/2)-(3/2)x^(-1/2)-(3/2)x^(-3/2)
解1)答案e^(4xsin2x)*(4sin2x+8xcos2x)2)答案[(4lny)-(3lnx)-3-(y/x)]/[(3lnx)-(4x/y)+(2lny)+2]3)答案(3y^2-2xy)/
x^3+2x^2+x=10^y3x^2+4x+1=10^y*y'*ln10y'=(3x^2+4x+1)/(10^y*ln10)=(3x^2+4x+1)/[(x^3+2x^2+x)*ln10]
等式两边取对数有:lny=1/3ln[x*(x^2+1)/(x-1)^2]化简得3lny=lnx+ln(x^2+1)-2ln|x-1|两边求导3y'/y=1/x+2x/(x^2+1)-2/(x-1)y
Iny=(-x)In3+2Inx(Iny)‘=-In3+2/xy'/y=-In3+2/xy'=(-In3+2/x)yy'=(-In3+2/x)[3^(-x)·(x²)]=(-x²I
3*2^(3x-2)*ln2写点过程好了,先对2^n求导=2^n*ln2,然后3x求导为3所以2^(3x-2)求导为3*2^(3x-2)*ln2注意!x^n的导数为n*x^(n-1),2^n求导并不等
3x^2y+x^3y'+3y^2y'-2=0=>(x^3+3y^2)y'=2-3x^2y∴y'=(2-3x^2y)/(x^3+3y^2)
1、令t=4x,则y=sint.y'=dy/dx=(dy/dt)*(dt/dx)=(cost)*4=4cos4x2、令t=x^2,则y=cosx^2.y'=dy/dx=(dy/dt)*(dt/dx)=
y=(3x+2)^4shez=3x+2suoyiy=z^4y'=(z^4)'*(3x+2)'=4z^3*3=12(3x+2)^3
y=-2xsinx+3sinxy'=-2sinx-2xcosx+3cosx
两边取对数lny=x^2*ln|x|两边求导y'/y=2xln|x|+x^2/xy'=y(2xln|x|+x)=x^(x^2)(2xln|x|+x)
y'=3(2-x²)²×(2-x²)'=3(2-x²)²×(-2x)=-6x(2-x²)²
积法则+链式y'=x'[arcsin(x/2)]+x[arcsin(x/2)]'=arcsin(x/2)+x*[1/根号(1-(x/2)^2)]*(x/2)'=arcsin(x/2)+x/[2*根号(
=2x
6x*exp(3x^2)exp()相当于e^()
(1)∵f(x)=sinx2+3cosx2=2sin(x2+π3),∴f(x)的最小正周期T=2π12=4π.当sin(x2+π3)=-1时,f(x)取得最小值-2;当sin(x2+π3)=1时,f(
解;y=(3x+5)²则y'=2(3x+5)×(3x+5)'=2(3x+5)×3=6(3x+5)=18x+30y=f(ax+b)的求导公式,y'=f'(ax+b)*(ax+b)'=af'(a