y=ln(x sqrt(4 x^2))的反函数
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y'=(lnlnx)'/lnlnx=(lnx)'/lnxlnlnx=1/xlnxlnlnx
chainruley=f(g(x))y'=g'(x)f'(g(x))
复合函数f(x)=lnxg(x)=ln[ln(x)]r(x)=ln{lnln(x)]}r'(x)=[1/lnln(x)]g'(x)=[1/lnln(x)][1/ln(x)]f'(x)=[1/lnln(
1/x再问:求写一下过程拍照再答:再问:不是是ln二次方x再答:再答:懂了么再答:再问:懂了再答:别忘了采纳最佳答案
y=(ln(ln(x))'/ln(ln(x))=(ln(x))'/(ln(x)(ln(ln(x)))=1/(xln(x)ln(ln(x)))
Y=[LN(1-X)]^2?Y'=2LN|1-X|/(1-X)(-1)=-2LN|1-X|/(1-X)
由y=ln(2-x)定义域:2-x>0,∴x<2,值域:y∈R.
答:y=ln(-x)y'(x)=[1/(-x)]*(-1)=1/x所以:y=ln(-x)的导数为y'(x)=1/x再问:非常感谢,,,那y=ln(3x+2)的导和y=ln(4x+2)的导分别怎么算呢?
y'=1/(tan(x/2))*(tan(x/2))'=1/(tan(x/2))*(sec^2(x/2))*(x/2)'=1/(2sin(x/2)*cos(x/2))=1/sin(x)=csc(x)
z可以分为两部分f(x)=√(4x-y^2)和g(x)=ln(x+y-1)z=f(x)+g(x)分布求定义域再求交集4x-y^2≥0x+y-1>0y^2≤4x且x>1-y
1,y=ln(1-x)y'=1/(1-x)*(1-x)'=1/(1-x)*(-1)=1/(x-1);2,y=ln[1/√(1-x)]=-ln√(1-x)y'=-1/√(1-x)*[√(1-x)]'=-
2x/(1+x^2)
如果是求导数的话,y'=(2x+e^x)/(x^2+e^x)
y'=ln(2x^-1)'=(x/2)*2*(-1)/x^2=-1/x
复合函数求导,应用链式法则y'=dy/dx=[dy/d(x^2+sinx)]*[d(x^2+sinx)/dx]=[1/(x^2+sinx)]*(2x+cosx)故y'=(2x+cosx)/(x^2+s
y=ln(3x-1)3x-1>0x>1/3即定义域为(1/3,+∞)y=log2/(4x-3)2/(4x-3)>04x-3>0x>3/4即定义域为(3/4,+∞)
x≤0时√x^2=-x所以y=0x>0时√x^2=x所以y=ln(2x+1)