y^2 2xy 9=0求隐函数
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![y^2 2xy 9=0求隐函数](/uploads/image/f/918800-8-0.jpg?t=y%5E2+2xy+9%3D0%E6%B1%82%E9%9A%90%E5%87%BD%E6%95%B0)
xy+e^y=y+1(1)求d^2y/dx^2在x=0处的值:(1)两边分别对x求导:y+xy'+e^yy'=y'y/y'+x+e^y=1(2)(2)两边对x再求导一次:(y'y'-yy'')/y'^
没说要和x=0或y=0围在一起,应该是所截的上面一部分y=sinx=1/2,0再问:pi是什么?再答:π
cos(xy)=x+y两边微分,得dx+dy-sin(xy)*(x*dy+y*dx)=0dx(1-ysin(xy))+dy(1-xsin(xy))=0dy/dx=(ysin(xy)-1)/(1-xsi
令F(x,y)=cos(xy)-x-yF'(x,y)x=-ysin(xy)-1对x求偏导F'(x,y)y=-xsin(xy)-1对y求偏导切线方程为:(x-0)/F'(x,y)=(y-1)/F'(x,
因为y=(x−0)2+(0−3)2+(x−4)2+(0−5)2,所以函数y是x轴上的点P(x,0)与两定点A(0,3)、B(4,5)距离之和.y的最小值就是|PA|+|PB|的最小值.由平面几何知识可
两边同时对X求导y+xy`=e^x+y`y`=(e^x-y)/(x-1)
设t=x2-6x+17,则t=(x-3)2+8,则函数y=f(x)等价为y=(12)t,则函数y=f(x)的定义域为R,∵y=(12)t,在定义域上为减函数,当x>3时,函数t=(x-3)2+8,单调
令u=x2-4x,则y=(13)u.∵x∈[0,5),则-4≤u<5,y=(13)u.而y=(13)u是定义域上的减函数,所以(13)5<y<(13)−4,即1243<y≤81,值域为(1243,81
将e^y看做以y为中间变量的复合函数因为e^y求导最终是一个关于x的函数,设y=f(x)g[f(x)]=g(y)=e^y=e^f(x)由此可以看出y只是一个中间变量,其实真正的自变量是xg(y)=e^
y'=-2sin2(x+y)-2y'sin2(x+y)(1+2sin2(x+y))y'=-2sin2(x+y)y'=-2sin2(x+y)/(1+2sin2(x+y))
答:正解,遇到形如x^x的形式就是这么做的.我算到答案跟你一样.
e^y-e^x=xy两边求导,得e^y*y'-e^x=y+xy'(e^y-x)y'=(e^x+y)所以y'=(e^x+y)/(e^y-x)x=0时,e^y-e^0=0,则e^y=1,则y=0所以y'(
由μ(x)=x2-5x+4>0,解得x>4或x<1,所以x∈(-∞,1)∪(4,+∞),当x∈(-∞,1)∪(4,+∞),{μ|μ=x2-5x+4}=R+,所以函数y=log13(x2-5x+4)的值
y'=[sin(x+y)]'(x+y)'=(1+y')cos(x+y)=cos(x+y)+y'cos(x+y)y'=cos(x+y)/[(1-cos(x+y)]y''=[cos(x+y]'(x+y)'
y'=-e^y-xe^y*y'(1+xe^y)y'=-e^yy'=-e^y/(1+xe^y)
两边对x求导得:y'+e^y+xe^y*y'=0将x=0,y=5代入得:y'(0)+e^5=0,y'(0)=-e^5
y'=-(e^y+xy'e^y)-y'=e^y+xy'e^yxy'e^y+y'=-e^y(xe^y+1)y'=-e^yy'=-e^y/(xe^y+1)y'=-e^y/(xe^y+1)
e^(x+y)+sin(xy)=1e^(x+y)*(1+y')+cos(xy)(y+xy')=0y'*[e*(x+y)+xcos(xy)]=-[ycos(xy)+e^(x+y)]y'=-[ycos(x
主要利用复合函数的求导:z=f(y),y=g(x),则z对x求导dz/dx=f'(y)*(dy/dx).等式左边对x求导过程:d(lny)/dx=(1/y)y',等式右边对x求导过程:d(x-y)/d