√x-1 √y-1=1
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【√x/(√x+√y)-√y/(√y-√x)-2√yx/x-y】/(1/√x-1/√y)*(√x+√y)=【√x/(√x+√y)+√y/(√x-√y)-2√yx/x-y】/(1/√x-1/√y)*(√
(1)两边对x求导,得2xy+x^2*dy/dx-1+dy/dx=0,所以dy/dx=(1-2xy)/(1+x^2)(2)两边对x求导,得√y+x*1/(2√y)*dy/dx=dy/dx,所以dy/d
2x-y+1/y=10x+1/y+x-y-2=8设x+1/y=ax-y-2=ba+b=4a^2+b^2=8b=4-aa^2+(4-a)^2=8a^2+a^2-8a+16=82a^2-8a+8=0(a-
由2x+y=1得y=1-2x代入2X^2+y^2=2(或根号二)得2x^2+(1-2X)^2=2(或根号二)6X^2-4x+1=2(或根号二)直接用求根公式即可
x=[(y^2-1)/2y]^2
由于绝对值与根号的非负性∴2x+y=-13x+2y=0解得x=-2y=3x*y=-6
再答:诚邀您加入百度知道团队“驾驭世界的数学”。
由4x+y-4x-6y+10=0得(4x-4x+1)+(y-6y+9)=0(2x-1)+(y-3)=0(2x-1)=0(y-3)=0x=1/2y=3代入所求算式即可求出结果(不好意思,看不清你的所求算
x=1+√2,y=1-√2x+y=2x-y=2√2[(1/(x-y)+1/(x+y)]-【2y/(x的平方-2xy+y的平方)】=[(x+y+x-y/(x-y)(x+y)]-【2y/(x-y)^2】=
因为x-1≥0,1-x≥0所以x=1,所以y=2所以x的y次方即1的2次方等于1
y/x哪个是分子?按理说y/x应该是x分之y,即y是分子再问:x是分子啊二次根式化简。。。。再答:注意应是分子/分母分子在前面的我前面都是按这个做的显然x>0,y>0则原式=(2x/3)*3√x+6x
∵x-√x-1=√y+3-y==>x-√x+1/4+y-√y+1/4=9/2==>(√x-1/2)²+(√y-1/2)²=9/2∴设√x-1/2=3cosa/√2,则√y-1/2=
2x²+1/2y²-2x-3y+5=0即2(x-1/2)²+1/2*(y-3)²=0两个平方式相加为0,那么两者都为0,所以得到x=1/2,y=3于是(2x√9
/>(1/x-y+1/x+y)÷x^2y^2/x^2-y^2=(2x)/(x^2-y^2)÷(x^2y^2)/(x^2-y^2)=(2x)/(x^2-y^2)÷(x^2-y^2)/(x^2y^2)=2
{[x*x-x*(x-1)]+y*y*y-5.2}*2-1={[5*5-5*(5-1)]+5*5*5-5.2}*2-1=(5+125-5.2)*2-1=259.8-1=258.8
y=ln(x-√x^2+a^2)-arcsin(a/x)y'=1/(x-√x^2+a^2)*(x-√x^2+a^2)'-1/√[1-(a/x)^2]*(a/x)'=1/(x-√x^2+a^2)*[1-
x≤0时√x^2=-x所以y=0x>0时√x^2=x所以y=ln(2x+1)
(2/3x√9x6x√y/x)(y√x/y-x²√1/x)=2/3*x*3√x6x*√(xy)/xy*√(xy)/y-x²√x/x=2x√x6√(xy)√(xy)-x√x=x√x7
y=x-x^(-1/2)所以y'=1-(-1/2)*x^(-3/2)=1+1/(2x√x)
由x-1≠0,-x²+x+2≥0得x≠1,(x-2)(x+1)≤0即:x≠1,-1≤x≤2取二者交集可得函数定义域为:x∈[-1,1)并(1,2]