解方程 1.4X^2-256=0 2.4(x-2/1)^2=1 3.-x^2+2x+3=0 4.3x^2+8x-3=0
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解方程 1.4X^2-256=0 2.4(x-2/1)^2=1 3.-x^2+2x+3=0 4.3x^2+8x-3=0 答案是X1和X2=多少,
![解方程 1.4X^2-256=0 2.4(x-2/1)^2=1 3.-x^2+2x+3=0 4.3x^2+8x-3=0](/uploads/image/z/10698361-25-1.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B+1.4X%5E2-256%3D0+2.4%28x-2%2F1%29%5E2%3D1+3.-x%5E2%2B2x%2B3%3D0+4.3x%5E2%2B8x-3%3D0)
1.4X^2-256=0
4x^2=256
x^2=64
x1=8,x2=-8
2.4(x-1/2)^2=1
(x-1/2)^2=1/4
x-1/2=1/2,x-1/2=-1/2
x1=1/2+1/2=1
x2=-1/2+1/2=0
3.-x^2+2x+3=0
x^2-2x-3=0
(x-3)*(x+1)=0
x1=3,x2=-1
4.3x^2+8x-3=0
(3x-1)*(x+3)=0
x1=1/3
x2=-3
4x^2=256
x^2=64
x1=8,x2=-8
2.4(x-1/2)^2=1
(x-1/2)^2=1/4
x-1/2=1/2,x-1/2=-1/2
x1=1/2+1/2=1
x2=-1/2+1/2=0
3.-x^2+2x+3=0
x^2-2x-3=0
(x-3)*(x+1)=0
x1=3,x2=-1
4.3x^2+8x-3=0
(3x-1)*(x+3)=0
x1=1/3
x2=-3
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