因式分解2mn(m+n)(m-n)-m2(m+1)(m-1)+n2(n+1)(n-1) x3+x2+x+6
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/11 17:02:47
因式分解2mn(m+n)(m-n)-m2(m+1)(m-1)+n2(n+1)(n-1) x3+x2+x+6
![因式分解2mn(m+n)(m-n)-m2(m+1)(m-1)+n2(n+1)(n-1) x3+x2+x+6](/uploads/image/z/15280647-15-7.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A32mn%28m%2Bn%29%28m-n%29-m2%28m%2B1%29%28m-1%29%2Bn2%28n%2B1%29%28n-1%29+x3%2Bx2%2Bx%2B6)
2mn(m+n)(m-n)-m2(m+1)(m-1)+n2(n+1)(n-1)
=2mn(m+n)(m-n)-m²(m²-1)+n²(n²-1)
=2mn(m+n)(m-n)-m^4+m²+n^4-n²
=2mn(m+n)(m-n)-(m^4-n^4)+(m²-n²)
=2mn(m+n)(m-n)-(m²-n²)(m²+n²)+(m²-n²)
=(m+n)(m-n)[2mn-(m²+n²)+1]
=(m+n)(m-n)[-(m²-2mn+n²)+1]
=(m+n)(m-n)[1-(m-n)^2]
=(m+n)(m-n)[1+(m-n)][1-(m-n)]
x^3+x^2+x+6
=(x^3 +2x^2)-(x^2 +2x)+(3x+6)
=x^2(x+2)-x(x+2)+3(x+2)
=(x+2)(x^2 -x+3)
=2mn(m+n)(m-n)-m²(m²-1)+n²(n²-1)
=2mn(m+n)(m-n)-m^4+m²+n^4-n²
=2mn(m+n)(m-n)-(m^4-n^4)+(m²-n²)
=2mn(m+n)(m-n)-(m²-n²)(m²+n²)+(m²-n²)
=(m+n)(m-n)[2mn-(m²+n²)+1]
=(m+n)(m-n)[-(m²-2mn+n²)+1]
=(m+n)(m-n)[1-(m-n)^2]
=(m+n)(m-n)[1+(m-n)][1-(m-n)]
x^3+x^2+x+6
=(x^3 +2x^2)-(x^2 +2x)+(3x+6)
=x^2(x+2)-x(x+2)+3(x+2)
=(x+2)(x^2 -x+3)
已知m2+n2+mn+m-n=-1则m分之一+n分之一=?
因式分解m^2-(n+1)m+n
因式分解(mn+m)2-(n+1)2
x2-(m2+n2-6n)x+m2+n2+2m-4n+1=0的两个实数根满足x1
已知m2-6m+9与|n+1|互为相反数,则m/m+n + n/m-n - m2/m2-n2 =
m-n-m方+n方分之m和1-m方-2mn-n2分之n 通分
因式分解m2一n2+m+n
如图已知实数m,n满足(m=n)2=1,(m-n)2=25,求m2+mn+n2的值
若方程(1+m2)x2-2m(1+n)x+m2+n2=0有实数根,则m和n应满足()
已知(m-n)2=8,(m+n)2=2,求(1)m2+n2(2)mn(3)m2+n2的值
如图,已知M(m,m2)、N(n,n2)是抛物线C:y=x2上两个不同点,且m2+n2=1,m+n≠0,直线l是线段MN
已知实数m、n满足m2+n2=1,求动点P(m+n,2m-n)的轨迹方程.