若x=24,则1/log2 (x)+1/log3 (x)+1/log4 (x)等于
若log2(log3(log4x)=log3(log4(log2y)=log4(log2(log3z)=0则x+y-z=
若log2[log3(log4)]=0,求x
若log4底[log3底(log2底x)]=0,则x=?
log2^(log3^x)=log3^(log4^y)=0则x+y=
log4(log2^x)=log2(log4^x)求log2^x
解方程log4(2-x)=log2(x-1)-1
log4^(2-X)=log2^(X-1)-1
log4(13-3x)=log2(x-1)
对数方程 log2^(x-1)=log4^x
log4 (x+2) = log2 (2x-1)
解方程:log2(3-x) - log4(x+5) =1
若log2【log3(log4 x)]=0,求x的值