关于初二几道分式的题!
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/08/11 17:02:14
关于初二几道分式的题!
计算
①.4a^b/3cd^ · 5c^d/4ab^ ÷ 2abc/3d
②.81-a^/a^ + 6a+9 ÷ a-9/2a+6 · a+3/a+9
计算
①.4a^b/3cd^ · 5c^d/4ab^ ÷ 2abc/3d
②.81-a^/a^ + 6a+9 ÷ a-9/2a+6 · a+3/a+9
![关于初二几道分式的题!](/uploads/image/z/15548652-36-2.jpg?t=%E5%85%B3%E4%BA%8E%E5%88%9D%E4%BA%8C%E5%87%A0%E9%81%93%E5%88%86%E5%BC%8F%E7%9A%84%E9%A2%98%21)
有点不太明白,
但是还是试试
1.(4a^2b/3cd^2)*(5c^2d/4ab^2)/(2abc/3d)
=(4a^2b*5c^2d*3d)/(3cd^2*4ab^2*2abc)
=(60a^2bc^2d^2)/(24a^2b^3c^2d^2)
=5/(2b^2)
2.(81-a²)/(a²+6a+9)÷(a-9)/(2a+6)×(a+3)/(a+9)
=(9-a)(9+a)/[(a+3)^2]*2(a+3)/(a-9)*(a+3)/(a+9)
=-2
但是还是试试
1.(4a^2b/3cd^2)*(5c^2d/4ab^2)/(2abc/3d)
=(4a^2b*5c^2d*3d)/(3cd^2*4ab^2*2abc)
=(60a^2bc^2d^2)/(24a^2b^3c^2d^2)
=5/(2b^2)
2.(81-a²)/(a²+6a+9)÷(a-9)/(2a+6)×(a+3)/(a+9)
=(9-a)(9+a)/[(a+3)^2]*2(a+3)/(a-9)*(a+3)/(a+9)
=-2