6道初二因式分解计算题!超简单(急)
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6道初二因式分解计算题!超简单(急)
10x^5-25^4+30^3
2a^4-12a^3+18a^2
63a^3b-28ab
9a(x-y)^2-18b(y-x)
(x^2-7)-4(x^2-7)+4
16(2a+b)^2-9(a-2b)^2
要求:需写出过程!
在发问后一小时内答题者,再附加20分!
10x^5-25^4+30^3
2a^4-12a^3+18a^2
63a^3b-28ab
9a(x-y)^2-18b(y-x)
(x^2-7)-4(x^2-7)+4
16(2a+b)^2-9(a-2b)^2
要求:需写出过程!
在发问后一小时内答题者,再附加20分!
![6道初二因式分解计算题!超简单(急)](/uploads/image/z/15611403-3-3.jpg?t=6%E9%81%93%E5%88%9D%E4%BA%8C%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E8%AE%A1%E7%AE%97%E9%A2%98%21%E8%B6%85%E7%AE%80%E5%8D%95%EF%BC%88%E6%80%A5%EF%BC%89)
10x^5-25x^4+30x^3 是不是这样?
=5x^3(x^2-5x+6)
=5x^3(x-2)(x-3)
2a^4-12a^3+18a^2
=2a^2(a^2-6a+9)
=2a^2(a-3)^2
63a^3b-28ab
=7ab(9a^2-4)
=7ab(3a+2)(3a-2)
9a(x-y)^2-18b(y-x)
=9a(x-y)^2+18b(x-y)
=9(x-y)(ax-ay+2b)
(x^2-7)^2-4(x^2-7)+4 是不是这样?
=(x^2-7-2)^2
=(x^2-9)^2
=(x+3)^2(x-3)^2
16(2a+b)^2-9(a-2b)^2
=[4(2a+b)]^2-[3(a-2b)]^2
=(8a+4b+3a-6b)(8a+4b-3a+6b)
=(11a-2b)(5a+10b)
=5(11a-2b)(a+2b)
=5x^3(x^2-5x+6)
=5x^3(x-2)(x-3)
2a^4-12a^3+18a^2
=2a^2(a^2-6a+9)
=2a^2(a-3)^2
63a^3b-28ab
=7ab(9a^2-4)
=7ab(3a+2)(3a-2)
9a(x-y)^2-18b(y-x)
=9a(x-y)^2+18b(x-y)
=9(x-y)(ax-ay+2b)
(x^2-7)^2-4(x^2-7)+4 是不是这样?
=(x^2-7-2)^2
=(x^2-9)^2
=(x+3)^2(x-3)^2
16(2a+b)^2-9(a-2b)^2
=[4(2a+b)]^2-[3(a-2b)]^2
=(8a+4b+3a-6b)(8a+4b-3a+6b)
=(11a-2b)(5a+10b)
=5(11a-2b)(a+2b)