原式=(x√y-y√x)/(x√y+y√x)- (y√x+x√y)/(y√x-x√y)今晚作业==请尽快
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/08 10:54:22
原式=(x√y-y√x)/(x√y+y√x)- (y√x+x√y)/(y√x-x√y)今晚作业==请尽快
原式=(x√y-y√x)/(x√y+y√x)-(y√x+x√y)/(y√x-x√y) 分母有理化
=(x√y-y√x)²/[(x√y+y√x)(x√y-y√x)]-(y√x+x√y)²/[(y√x+x√y)(y√x-x√y)]
=[x²y-2xy√(xy)+xy²]/(x²y-xy²)-[xy²+2xy√(xy)+x²y]/(xy²-x²y)
=[x²y-2xy√(xy)+xy²]/(x²y-xy²)+[xy²+2xy√(xy)+x²y]/(x²y-xy²)
=[x²y-2xy√(xy)+xy²+xy²+2xy√(xy)+x²y]/(x²y-xy²)
=(2x²y+2xy²)/(x²y-xy²)
=[2xy(x+y)]/[xy(x-y)]
=2(x+y)/(x-y)
=(x√y-y√x)²/[(x√y+y√x)(x√y-y√x)]-(y√x+x√y)²/[(y√x+x√y)(y√x-x√y)]
=[x²y-2xy√(xy)+xy²]/(x²y-xy²)-[xy²+2xy√(xy)+x²y]/(xy²-x²y)
=[x²y-2xy√(xy)+xy²]/(x²y-xy²)+[xy²+2xy√(xy)+x²y]/(x²y-xy²)
=[x²y-2xy√(xy)+xy²+xy²+2xy√(xy)+x²y]/(x²y-xy²)
=(2x²y+2xy²)/(x²y-xy²)
=[2xy(x+y)]/[xy(x-y)]
=2(x+y)/(x-y)
数学题化简再求值(1/x-y+1/x+y)÷x^2 y^2/x^2-y^2,其中x=3,y=-√2
已知:x*x+√3y=√5,y*y+√3x=√5,且x≠y,求 y/x+x/y
化简【√x/(√x+√y)-√y/(√y-√x)-2√yx/x-y】/(1/√x-1/√y)*(√x+√y),其中x=
先化简再求值 [(1/(x-y)+1/(x+y)]-【2y/(x的平方-2xy+y的平方)】 其中x=1+√2,y=1-
设P(x,y)是圆x²+y²+8y+12=0上的一点,√(x²+y²-2x-2y
y=ln(x-√x^2+a^2)-arcsin(a/x) 求y' y=ln(x+√1+x^2) 求y‘
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)
已知(x-2)+√y-x+1=0,求x+y的平方根
y=(√x)+√(x+1)
若x>0,y>0,且√x(√x+√y)=3√y(√x+5√y),求(2x+2√xy+3y)/(x-√xy+y)的值.
若x、y为整数,√x(√x+√y)=3√y(√x+5√y),试求2x+(√xy)+3y除以x+(√xy)+y
y=√x+xe^x 求y'