两题计算题 1、2/a²-4*[(a²+4/4a)-1] 2、[(a/a-1)-1] /(1/a
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两题计算题 1、2/a²-4*[(a²+4/4a)-1] 2、[(a/a-1)-1] /(1/a²-2a+1)
![两题计算题 1、2/a²-4*[(a²+4/4a)-1] 2、[(a/a-1)-1] /(1/a](/uploads/image/z/15925354-34-4.jpg?t=%E4%B8%A4%E9%A2%98%E8%AE%A1%E7%AE%97%E9%A2%98+1%E3%80%812%2Fa%26%23178%3B-4%2A%5B%28a%26%23178%3B%2B4%2F4a%29-1%5D+2%E3%80%81%5B%EF%BC%88a%2Fa-1%29-1%5D+%2F%281%2Fa%26%23)
2/(a²-4)*[(a²+4)/4a-1]
=2/(a²-4)*[(a²+4-4a)/4a]
=2/(a²-4)*(a²-4a+4)/4a
=2/[(a-2)(a+2)]*(a-2)²/4a
=1/(a+2)*(a-2)/2a
=(a-2)/[2a(a+2)]
=(a-2)/(2a^2+4)
[a/(a-1)-1] /[1/(a²-2a+1)]
=[(a-a+1)/(a-1)] /[1/(a-1)²]
=[1/(a-1)] /[1/(a-1)²]
=1/(a-1)*(a-1)²
=a-1
=2/(a²-4)*[(a²+4-4a)/4a]
=2/(a²-4)*(a²-4a+4)/4a
=2/[(a-2)(a+2)]*(a-2)²/4a
=1/(a+2)*(a-2)/2a
=(a-2)/[2a(a+2)]
=(a-2)/(2a^2+4)
[a/(a-1)-1] /[1/(a²-2a+1)]
=[(a-a+1)/(a-1)] /[1/(a-1)²]
=[1/(a-1)] /[1/(a-1)²]
=1/(a-1)*(a-1)²
=a-1
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