计算下面各定积分 1)∫[0,1]√(4-x^2)dx 2)∫[-2,0]dx/x^2+2x+2 3)∫[0,1]xe^
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计算下面各定积分 1)∫[0,1]√(4-x^2)dx 2)∫[-2,0]dx/x^2+2x+2 3)∫[0,1]xe^xdx 4)∫[1,e]xlnxdx
计算下面各定积分
1)∫[0,1]√(4-x^2)dx
2)∫[-2,0]dx/x^2+2x+2
3)∫[0,1]xe^xdx
4)∫[1,e]xlnxdx
计算下面各定积分
1)∫[0,1]√(4-x^2)dx
2)∫[-2,0]dx/x^2+2x+2
3)∫[0,1]xe^xdx
4)∫[1,e]xlnxdx
![计算下面各定积分 1)∫[0,1]√(4-x^2)dx 2)∫[-2,0]dx/x^2+2x+2 3)∫[0,1]xe^](/uploads/image/z/16050090-66-0.jpg?t=%E8%AE%A1%E7%AE%97%E4%B8%8B%E9%9D%A2%E5%90%84%E5%AE%9A%E7%A7%AF%E5%88%86+1%EF%BC%89%E2%88%AB%5B0%2C1%5D%E2%88%9A%284-x%5E2%29dx+2%EF%BC%89%E2%88%AB%5B-2%2C0%5Ddx%2Fx%5E2%2B2x%2B2+3%EF%BC%89%E2%88%AB%5B0%2C1%5Dxe%5E)
∫(0->1) √(4-x²) dx
Let x = 2siny,dx = 2cosy dy
x = 0,y = 0,x = 1,y = π/6
=> ∫(0->π/6) (2cosy)(2cosy) dy
= 2∫(0->π/6) (1+cos2y) dy
= 2(y+1/2 * sin2y)
= 2[π/6+1/2 * sin(π/3)]
= π/3 + √3/2
∫(-2->0) dx/(x²+2x+2)
= ∫(-2->0) dx/[(x+1)²+1]
= arctan(x+1)
= arctan(1) - arctan(-1)
= π/4 - (-π/4)
= π/2
∫(0->1) xe^x dx
= ∫(0->1) x de^x
= xe^x - ∫(0->1) e^x dx
= e - (e - 1)
= 1
∫(1->e) xlnx dx
= ∫(1->e) lnx d(x²/2)
= (1/2)x²lnx - (1/2)∫(1->e) x² * 1/x dx
= (1/2)(e² - 0) - (1/4)(e² - 1)
= (1+e²)/4
Let x = 2siny,dx = 2cosy dy
x = 0,y = 0,x = 1,y = π/6
=> ∫(0->π/6) (2cosy)(2cosy) dy
= 2∫(0->π/6) (1+cos2y) dy
= 2(y+1/2 * sin2y)
= 2[π/6+1/2 * sin(π/3)]
= π/3 + √3/2
∫(-2->0) dx/(x²+2x+2)
= ∫(-2->0) dx/[(x+1)²+1]
= arctan(x+1)
= arctan(1) - arctan(-1)
= π/4 - (-π/4)
= π/2
∫(0->1) xe^x dx
= ∫(0->1) x de^x
= xe^x - ∫(0->1) e^x dx
= e - (e - 1)
= 1
∫(1->e) xlnx dx
= ∫(1->e) lnx d(x²/2)
= (1/2)x²lnx - (1/2)∫(1->e) x² * 1/x dx
= (1/2)(e² - 0) - (1/4)(e² - 1)
= (1+e²)/4
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