来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/08/19 07:33:18
1、数学计算题,要过程,一定会采纳~
![](http://img.wesiedu.com/upload/2/d9/2d9abfc138bf1e0c418382f9e97bf3a7.jpg)
原式=(x-6y)/[(x+2y)(x-2y)]+2y/[x(x-2y]
=[x(x-6y)/[x(x+2y)(x-2y)]+[2y(x+2y)]/[x(x+2y)(x-2y)]
=[x²-6xy+2xy+4y²]/[x(x+2y)(x-2y)]
=(x²-4xy+4y²)/[x(x+2y)(x-2y)]
=(x-2y)²/[x(x+2y)(x-2y)]
=(x-2y)/[x(x+2y)]