关于初二分式化简的问题
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/21 07:37:41
关于初二分式化简的问题
a+2a+1-a+3a+2-a+4a+3+a+5a+4 怎么化简?
...打不出来分数啊... 看图吧...
![](http://img.wesiedu.com/upload/e/47/e472580c8b645deb20c0bbd1a85abe1c.jpg)
a+2a+1-a+3a+2-a+4a+3+a+5a+4 怎么化简?
...打不出来分数啊... 看图吧...
![](http://img.wesiedu.com/upload/e/47/e472580c8b645deb20c0bbd1a85abe1c.jpg)
![关于初二分式化简的问题](/uploads/image/z/16376999-23-9.jpg?t=%E5%85%B3%E4%BA%8E%E5%88%9D%E4%BA%8C%E5%88%86%E5%BC%8F%E5%8C%96%E7%AE%80%E7%9A%84%E9%97%AE%E9%A2%98)
这里没有分式啊,合并同类项
(a+2)/(a+1)=1+1/(a+1)
(a+3)/(a+2)=1+1/(a+2)
(a+4)/(a+3)=1+1/(a+3)
(a+5)/(a+4)=
原式样=1+1/(a+1)-(1+1/(a+2))-((a+4)/(a+3)=1+1/(a+3))+1+1/(a+4)
=1/(a+1)-1/(a+2)-1/(a+3)+1/(a+4)
=1/(a+1)(a+2)-1/(a+3)(a+4)
=(4a+10)/(a+1)(a+2)(a+3)(a+4)
(a+2)/(a+1)=1+1/(a+1)
(a+3)/(a+2)=1+1/(a+2)
(a+4)/(a+3)=1+1/(a+3)
(a+5)/(a+4)=
原式样=1+1/(a+1)-(1+1/(a+2))-((a+4)/(a+3)=1+1/(a+3))+1+1/(a+4)
=1/(a+1)-1/(a+2)-1/(a+3)+1/(a+4)
=1/(a+1)(a+2)-1/(a+3)(a+4)
=(4a+10)/(a+1)(a+2)(a+3)(a+4)