机械波的计算题 A pulse of width 32.6 cm bouncing back and forth on
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机械波的计算题
A pulse of width 32.6 cm bouncing back and forth on a stretched string of
length 25.7m and mass per unit length μ = 1.65 × 10−3 kg/m is observed to
take 12.8 s to make 13 round trips.What is the tension on the string?
A pulse of width 32.6 cm bouncing back and forth on a stretched string of
length 25.7m and mass per unit length μ = 1.65 × 10−3 kg/m is observed to
take 12.8 s to make 13 round trips.What is the tension on the string?
![机械波的计算题 A pulse of width 32.6 cm bouncing back and forth on](/uploads/image/z/16410116-20-6.jpg?t=%E6%9C%BA%E6%A2%B0%E6%B3%A2%E7%9A%84%E8%AE%A1%E7%AE%97%E9%A2%98+A+pulse+of+width+32.6+cm+bouncing+back+and+forth+on)
并不是很确定脉冲的宽度的影响,但是弦线的两端是固定的,脉冲的宽度并不会增加波走过的距离.
走过的距离为13*2*25.7=668.2(m),时间为12.8(s)由此得到波速v=52.2 m/s.
再由弦线上的波速公式v=√(T/μ),此处μ为弦线的线质量密度.
T=v^2 *μ=(52.2)^2 *1.65×10-3=4.5(N)
走过的距离为13*2*25.7=668.2(m),时间为12.8(s)由此得到波速v=52.2 m/s.
再由弦线上的波速公式v=√(T/μ),此处μ为弦线的线质量密度.
T=v^2 *μ=(52.2)^2 *1.65×10-3=4.5(N)
back and forth withone
back and forth 歌词
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go back and forth
moving back and forth only a yard of two from the toy 翻译
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