求一道因式分解题步骤和答案、加急~(xy+1)(x+1)(y+1)+xy=(xy+1)(xy+x+y+1)+xy
一道因式分解题,急xyz+xy+yz+zx+x+y+z+1
用换元法分解因式 (xy+1)(x+1)(y+1)+xy
xy-1+x-y
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
求解一道数学题;(xy-1)^2+(x+y-2)(x+y-2xy) 分解因式
当x=3,y=3分之1时,求代数出3xy-[2xy-2(xy-2分之3xy)+xy]+3xy的值
已知XY为正数,X+Y=1 求1/XY+XY的最小值
先化简,再求值 ⒈2(Xy+Xy)-3(Xy-xy)-4Xy,其中X=1,y=-1
已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值
已知3/(x-y)=1/xy 求(-x-2xy+y)/ (2x+3xy-2y)
已知xy>0,证明xy+xy/1+x/y+y/x>=4
(x+y-2xy)(x+y-2)+(1-xy)²