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1-(x-y)/(x+2y)÷(x²-y²)/(x²+4xy+4y²),化简

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1-(x-y)/(x+2y)÷(x²-y²)/(x²+4xy+4y²),化简
1-(x-y)/(x+2y)÷(x²-y²)/(x²+4xy+4y²),化简
原式=1-(x-y)/(x+2y)÷(x+y)(x-y)/(x+2y)²
=1-(x-y)/(x+2y)*(x+2y)²/(x+y)(x-y)
=1-(x+2y)/(x+y)
=[(x+y)-(x+2y)]/(x+y)
=-y/(x+y)
再问: http://zhidao.baidu.com/question/439075277.html?quesup2&oldq=1