解下列方程:(1)(x+1)2=9  
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解下列方程:
(1)(x+1)2=9
(2)x2-6x+8=0
(3)4x(2x-1)=5(2x-1)
(4)(x-1)(x+3)=32.
(1)(x+1)2=9
(2)x2-6x+8=0
(3)4x(2x-1)=5(2x-1)
(4)(x-1)(x+3)=32.
![解下列方程:(1)(x+1)2=9  ](/uploads/image/z/16601717-29-7.jpg?t=%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%9A%EF%BC%881%EF%BC%89%EF%BC%88x%2B1%EF%BC%892%3D9%26nbsp%3B%E3%80%80%E3%80%80%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp)
(1)开方得:x+1=3或x+1=-3,
解得:x1=2,x2=-4;
(2)分解因式得:(x-2)(x-4)=0,
可得x-2=0或x-4=0,
解得:x1=2,x2=4;
(3)方程变形得:(4x-5)(2x-1)=0,
可得4x-5=0或2x-1=0,
解得:x1=
5
4,x2=
1
2;
(4)方程整理得:x2+2x-35=0,
分解因式得:(x-5)(x+7)=0,
解得:x1=5,x2=-7.
解得:x1=2,x2=-4;
(2)分解因式得:(x-2)(x-4)=0,
可得x-2=0或x-4=0,
解得:x1=2,x2=4;
(3)方程变形得:(4x-5)(2x-1)=0,
可得4x-5=0或2x-1=0,
解得:x1=
5
4,x2=
1
2;
(4)方程整理得:x2+2x-35=0,
分解因式得:(x-5)(x+7)=0,
解得:x1=5,x2=-7.