分式计算题:(x√x+x√y)/(xy-y2)-(+√xy+y)/(x√x-y√y)求解
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分式计算题:(x√x+x√y)/(xy-y2)-(+√xy+y)/(x√x-y√y)求解
原式=[x(√x+√y)]/[y(x-y)]-[(√x)²+√x×√y+(√y)²]/[(√x)³-(√y)³]
=[x(√x+√y)]/[y(√x+√y)(√x-√y)]-[(√x)²+√x×√y+(√y)²]/﹛(√x-√y)[(√x)²+√x×√y+(√y)²]﹜
=x/[y(√x-√y)]-1/(√x-√y)
=x/[y(√x-√y)]-y/[y(√x-√y)]
=(x-y)/[y(√x-√y)]
=[(√x+√y)(√x-√y)]/[y(√x-√y)]
=(√x+√y)/y
=[x(√x+√y)]/[y(√x+√y)(√x-√y)]-[(√x)²+√x×√y+(√y)²]/﹛(√x-√y)[(√x)²+√x×√y+(√y)²]﹜
=x/[y(√x-√y)]-1/(√x-√y)
=x/[y(√x-√y)]-y/[y(√x-√y)]
=(x-y)/[y(√x-√y)]
=[(√x+√y)(√x-√y)]/[y(√x-√y)]
=(√x+√y)/y
(√xy -xy分之x+√xy)除以√xy -y分之x-y(x>0,y.0)
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