1.(1)99*9² (2)51²+49² 2.(1)a(a-2b)-(a-b)²
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/11 23:01:37
1.(1)99*9² (2)51²+49² 2.(1)a(a-2b)-(a-b)² (初一数学,完全平方公式,
![1.(1)99*9² (2)51²+49² 2.(1)a(a-2b)-(a-b)²](/uploads/image/z/17166699-27-9.jpg?t=1.%EF%BC%881%EF%BC%8999%2A9%26sup2%3B+%EF%BC%882%EF%BC%8951%26sup2%3B%2B49%26sup2%3B+2.%EF%BC%881%EF%BC%89a%EF%BC%88a-2b%EF%BC%89-%EF%BC%88a-b%EF%BC%89%26sup2)
1.(1)99*92
=99*(10-1)2
=99*(102-2*10+12)
=99*(100-20+1)
=99*100-99*20+99
=9900-1980+99
=9900+99-1980
=8019
(2)512+492
=(50+1)2+(50-1)2
=(502+2*50+12)+(502-2*50+12)
=2*(502+12)
=2*2501
=5002
2.(1)a(a-2b)-(a-b)2
=a2-2ab-(a2-2ab+b2)
=a2-2ab-a2+2ab-b2
=-b2
=99*(10-1)2
=99*(102-2*10+12)
=99*(100-20+1)
=99*100-99*20+99
=9900-1980+99
=9900+99-1980
=8019
(2)512+492
=(50+1)2+(50-1)2
=(502+2*50+12)+(502-2*50+12)
=2*(502+12)
=2*2501
=5002
2.(1)a(a-2b)-(a-b)2
=a2-2ab-(a2-2ab+b2)
=a2-2ab-a2+2ab-b2
=-b2
2(a²b+3ab²)-3(a²b-1)-2a²b-2
化简:(b²-a²)/(a²-2ab+b²)
1.(b²+2a²)(2a²-b²) 2.(4x²-4y²)
数学因式分解计算(a²-b²)/(a²b-ab²)÷ [1+(a²+b
已知(a-2)²+(b+1)²=0,求代数式3a²b+ab²-3a²b
(a²+b²)²-4a²b²化简
1.a²+b²=6,ab=1,则(a-b)²=
(a+b-1)²
(a+b)/(2a+2b)乘(a²+b²)/(a²-b²) 计算
1.-9a²+4b² 2.(2a-b+c)²-(3a+2b)² 3. 4x&su
1.定义运算 a#b=ab²-2[a²b-3(b²a-4ba²)] ,那么,1#
因式分解:1、16(a-b)²-9(a+b)²2、x^5y-xy3、2010²-2009&