数列an中,a1=8,a4=2,且满足a(n+2)-2*a(n+1)+an=0(n∈N*).
已知数列{an}满足:a1=1,且an-a(n-1)=2n.求a2,a3,a4.求数列{an}通项an
数列{an}中,a1=8,a4=2且满足an+2=2an+1-an( n∈N*)
在数列an中,a1=1,且满足a(n+1)=3an +2n,求an
高一数列通项.数列{an}中 a1=2 ,a4=8且满足 a(n-2)=2a(n-1) - an (n∈N+)求数列{a
数列{An}中,A1=8,A4=2,且满足A(n+2)=2A(n+1)-An,(n属于自然数),设Bn=1/n(12-A
已知数列an满足,a1=1,an>0且a(n+1)×更号下(4+1/an^2)=1(n∈N+)
数列{an}中a1=8,a4=2,且满足a(n+2)-2a(n+1)+an=0求通项公式(2)设Sn=‖a1‖+‖a2‖
已知数列{an}中,a1=3,且满足a(n+1)-3an=2x3^n(n属于N*)
已知数列an中满足a1=1且当n.=2时,2an*a*(n-1)+an-a(n-1)=0,求通项公式an
1.已知数列{An}满足A1=1,An= 2A(n-1)+2(n∈N,且N≥2)
已知数列{an}满足a1=33,a(n+1)-an=2n,求an/n的最小值
高二必修五数列相关解答题 已知数列{an}满足a n+1 = 2an+1(n∈N*),且a1=1