(1+x)(x-1/x²+x-1-x/x的3次方-x)
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(1+x)(x-1/x²+x-1-x/x的3次方-x)
3x-6/x²-4÷(x+2/x²+4x+4) -2
3x-6/x²-4÷(x+2/x²+4x+4) -2
![(1+x)(x-1/x²+x-1-x/x的3次方-x)](/uploads/image/z/17702148-12-8.jpg?t=%281%2Bx%29%28x-1%2Fx%26sup2%3B%2Bx-1-x%2Fx%E7%9A%843%E6%AC%A1%E6%96%B9-x%EF%BC%89)
(1+x)(x-1/x²+x-1-x/x的3次方-x)
=(1+x)(x-1/x²+x-1)-(1+x)(1-x)/x的3次方-x)
=(1+x)(x-1/x(x+1)-(1+x)(1-x)/x(x+1)(x-1)
=(x-1)/x+1/x=x/x=1
3x-6/x²-4÷(x+2/x²+4x+4) -2
=3(x-2)/(x+2)(x-2)÷(x+2/(x+2)² -2
=3/(x+2)÷1/(x+2)-2
=3-2=1
=(1+x)(x-1/x²+x-1)-(1+x)(1-x)/x的3次方-x)
=(1+x)(x-1/x(x+1)-(1+x)(1-x)/x(x+1)(x-1)
=(x-1)/x+1/x=x/x=1
3x-6/x²-4÷(x+2/x²+4x+4) -2
=3(x-2)/(x+2)(x-2)÷(x+2/(x+2)² -2
=3/(x+2)÷1/(x+2)-2
=3-2=1
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