1.已知a^2-2ab+b^2+2(a-b)+1=0,则a-b=________2.能否将多项式4a^4+1再添一项,使
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1.已知a^2-2ab+b^2+2(a-b)+1=0,则a-b=________2.能否将多项式4a^4+1再添一项,使它成为完全平方式?
3.分解因式(1)5x^2-45y^2 (2)25x^3+10x^2y+xy^2 (3)x^5-xy^4
4.已知a(a-1)-(a^2-b)=3,求a^2+b^2-2ab的值
3.分解因式(1)5x^2-45y^2 (2)25x^3+10x^2y+xy^2 (3)x^5-xy^4
4.已知a(a-1)-(a^2-b)=3,求a^2+b^2-2ab的值
![1.已知a^2-2ab+b^2+2(a-b)+1=0,则a-b=________2.能否将多项式4a^4+1再添一项,使](/uploads/image/z/18527019-51-9.jpg?t=1.%E5%B7%B2%E7%9F%A5a%5E2-2ab%2Bb%5E2%2B2%28a-b%29%2B1%3D0%2C%E5%88%99a-b%3D________2.%E8%83%BD%E5%90%A6%E5%B0%86%E5%A4%9A%E9%A1%B9%E5%BC%8F4a%5E4%2B1%E5%86%8D%E6%B7%BB%E4%B8%80%E9%A1%B9%2C%E4%BD%BF)
a^2-2ab+b^2+2(a-b)+1=0
(a-b)^2+2(a-b)+1=0
(a-b+1)^2=0
a-b+1=0
a-b=-1
4a^4±4a^2+1=(2a^2±1)^2
5x^2-45y^2
=5(x^2-9y^2)
=5(x+3y)(x-3y)
25x^3+10x^2y+xy^2
=x(25x^2+10xy+y^2)
=x(5x+y)^2
x^5-xy^4
=x(x^4-y^4)
=x(x^2-y^2)(x^2+y^2)
=x(x-y)(x+y)(x^2+y^2)
a(a-1)-(a^2-b)=3,求a^2+b^2-2ab的值
a(a-1)-(a^2-b)=3
a^2-a-a^2+b=3
b-a=3
a^2+b^2-2ab
=(a-b)^2
=( b-a)^2
=3^2
=9
(a-b)^2+2(a-b)+1=0
(a-b+1)^2=0
a-b+1=0
a-b=-1
4a^4±4a^2+1=(2a^2±1)^2
5x^2-45y^2
=5(x^2-9y^2)
=5(x+3y)(x-3y)
25x^3+10x^2y+xy^2
=x(25x^2+10xy+y^2)
=x(5x+y)^2
x^5-xy^4
=x(x^4-y^4)
=x(x^2-y^2)(x^2+y^2)
=x(x-y)(x+y)(x^2+y^2)
a(a-1)-(a^2-b)=3,求a^2+b^2-2ab的值
a(a-1)-(a^2-b)=3
a^2-a-a^2+b=3
b-a=3
a^2+b^2-2ab
=(a-b)^2
=( b-a)^2
=3^2
=9
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