lim[f(2x)/x]=1/3 则 lim[x/f(3x)]= (x-0)
都是x趋向与0的1.lim {ln[1+x+f(x)/x]}/x=3 为什么可以推出 lim f(x)/x=02.lim
设lim(x→0)[f(x)-3]/x^2=100,求lim(x→0)f(x)
若lim[x/f(3x)]=2(x趋向于0),则lim[f(2x)/x]=?(x趋向于0)
已知x-->0时,lim{ln[1+f(x)/tanx]/(3^x-1)}=2,求lim(x-->0)[f(x)/x^2
f(x)为多项式且lim(x->∞)(f(x)-4x^3)/x^2=1,lim(x->0)f(x)/x=5,求F(X)的
lim(x趋近于0)[sin6x+xf(x)]/x^3=0,则lim(x趋近于0)[6+f(x)]/x^2=?
假设lim(x趋于0)[(sin6x+xf(x))/x^3]=0,则lim(x趋于0)[(6+f(x))/x^2]=?,
已知lim(x→0) f(x)/(1-cosx) =2 求lim(x→0) [1+f(x)]^½
f(x)在x=0的某邻域内二阶可导,且lim (x->0) (sin3x/x^3 + f(x)/x^2) =0,求lim
已知lim(x→0)[f(3x)/x]=3 求lim(x→0) [2x/f(5x)]
求极限当x→0若lim[sin6x+x f(x)]/x^3=0,求lim[6+ f(x)]/x^2
f(x)=[x+1,x3],lim(x趋于3)f(x)是否存在?为什么