2log3 2-log3 32/9+log3 8-3^2+log3 5

来源：学生作业帮编辑：百度作业网作业帮分类：数学作业时间：2024/08/15 21:18:24

2log₃ 2-log₃(32/9)+log₃8-3^(2+log₃5)
=log₃4-log₃(32/9)+log₃8-3^2*3^log₃5
=log₃(4÷32/9×8) -9*5
=log₃(4×9/32×8)-45
=log₃9-45
=2-45
=-43
最后的式子指数应该加括号,试了半天

log2(3)+log3(5)+log3(2)=? 2log3底2-log3底32/9+log3底8 (log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7) 解不等式（2+log3 x)log3 x>log3 (9x) log3(2)*log8(9) 计算log3[(9^2 * 27^(1/3))/3^(log3 234)] log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2) 一道对数计算,log3(27/5)+log3(2/3)-log3(6/5) (log2(3)+log8(9))x(log3(4)+log9(8)+log3(2)) (log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程 log3 5-log3 15+1/2log9 27 的值 log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写