分式的基本性质 (9 13:33:3)
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/08/08 19:43:05
分式的基本性质 (9 13:33:3)
1,(2x-1)/xy=____
2,若a=2/3,则(a2-2a-3)/(a2-7a+12)的值等于____
3,已知x2-4x+1=0,求x4+1/x4
1,(2x-1)/xy=____
2,若a=2/3,则(a2-2a-3)/(a2-7a+12)的值等于____
3,已知x2-4x+1=0,求x4+1/x4
![分式的基本性质 (9 13:33:3)](/uploads/image/z/19121529-57-9.jpg?t=%E5%88%86%E5%BC%8F%E7%9A%84%E5%9F%BA%E6%9C%AC%E6%80%A7%E8%B4%A8+%289+13%3A33%3A3%29)
1.分解为:2/y-1/xy
2.(a2-2a-3)/(a2-7a+12)
=(a-3)(a+1)/(a-3)(a-4)
=(a+1)/(a-4)
将a=2/3代入得到:
=(a+1)/(a-4)=5/-10=-1/2
3.解方程:x2-4x+1=0 得到:x=2± √3
代入x4+1/x4 =97+56√3+1/(97+56√3)
2.(a2-2a-3)/(a2-7a+12)
=(a-3)(a+1)/(a-3)(a-4)
=(a+1)/(a-4)
将a=2/3代入得到:
=(a+1)/(a-4)=5/-10=-1/2
3.解方程:x2-4x+1=0 得到:x=2± √3
代入x4+1/x4 =97+56√3+1/(97+56√3)