帮我分析下这个三元三次方程,
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/07/06 00:46:38
帮我分析下这个三元三次方程,
x*x*x + y*y*y = 1 + z*z*z 已知条件 x
z都是正整数,再次重申下,我知道所有结果,只要其三者之间的关系,可以用不等式或者等式表达,我已经找出来,1.4y > z
x*x*x + y*y*y = 1 + z*z*z 已知条件 x
z都是正整数,再次重申下,我知道所有结果,只要其三者之间的关系,可以用不等式或者等式表达,我已经找出来,1.4y > z
![帮我分析下这个三元三次方程,](/uploads/image/z/19582726-22-6.jpg?t=%E5%B8%AE%E6%88%91%E5%88%86%E6%9E%90%E4%B8%8B%E8%BF%99%E4%B8%AA%E4%B8%89%E5%85%83%E4%B8%89%E6%AC%A1%E6%96%B9%E7%A8%8B%2C)
public class XYZPuzzle {
public static final int MAXSIZE = 9750;
public static void work() {
int z;
double temp;
int count = 0;
long[] cubeNums = new long[MAXSIZE];
for (int i = 0; i < MAXSIZE; i++) {
cubeNums[i] = ((long) i + 1L) * ((long) i + 1L) * ((long) i + 1L);
}
for (int x = 2; x
public static final int MAXSIZE = 9750;
public static void work() {
int z;
double temp;
int count = 0;
long[] cubeNums = new long[MAXSIZE];
for (int i = 0; i < MAXSIZE; i++) {
cubeNums[i] = ((long) i + 1L) * ((long) i + 1L) * ((long) i + 1L);
}
for (int x = 2; x