x²-2x+1=0 x等于?
已知2x²-6x-﹙1/2﹚˜²=0,求x²-3x/x⁴-6x
已知x²+3x-1=0,求x-1/x和x²+1/x²的值.
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
x²+3x-2=0,x²-6x-6=0,3x²-4x-1=0,3x²+10x+3
解方程①(x+3/x-1)²-5(x+3/x-1)+6=0 ②x²-2/x+3-6x+18/x
28(6):函数f(x)={log2(x),(x>0);-x²-2x+1,x≤0},若关于x的方程f[f(x)
(x²-7x+12)(x²+x+1)>0,
5/x²+x-1/x²-x=0
6x+(2x²-3x)-(x²-1)
(x+2)(x-3)(x-6)(x-1)=0
x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x)