2^x(4^y+1)+2^y(4^x+1)/(4^x+1)(4^y+1)求化简啊
1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y
(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)
1 4(x-y+1)+y(y-2x)
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
已知4x=9y求(1)x+y/y (2)y-x/2x
把4(x-y+1)+y(y-2x)因式分解
4(x-y+1)+y(y-2x)
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
化简:[(2x-y)平方+(2x+y)(2x-y)-4x(x-y+1)]÷2x
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y