{(√1+y)/〔(√(1+y)-√(1-y)〕}{(1+y)/y - √(1/y^2 - 1)}
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{(√1+y)/〔(√(1+y)-√(1-y)〕}{(1+y)/y - √(1/y^2 - 1)}
就是把它化简就可以了
让我看得懂就可以了
就是把它化简就可以了
让我看得懂就可以了
![{(√1+y)/〔(√(1+y)-√(1-y)〕}{(1+y)/y - √(1/y^2 - 1)}](/uploads/image/z/19895662-46-2.jpg?t=%EF%BD%9B%EF%BC%88%E2%88%9A1%2By%EF%BC%89%2F%E3%80%94%EF%BC%88%E2%88%9A%EF%BC%881%2By%EF%BC%89-%E2%88%9A%EF%BC%881-y%EF%BC%89%E3%80%95%EF%BD%9D%EF%BD%9B%EF%BC%881%2By%EF%BC%89%2Fy+-+%E2%88%9A%EF%BC%881%2Fy%5E2+-+1%29%EF%BD%9D)
{√(1+y)/[√(1+y)-√(1-y)]}{(1+y)/y-√(1/y²-1)}
={(√1+y)[√(1+y)+√(1-y)]/[√(1+y)-√(1-y)][√(1+y)+√(1-y)]}{(1+y)/y -√[(1-y²)/y²]}
={[1+y+√(1-y²)]/[(1+y)-(1-y)]}{(1+y)/y -√(1-y²)/y}
={[(1+y)+√(1-y²)]/2y}{[(1+y)-√(1-y²)]/y}
=[(1+y)²-(1-y²)]/2y²
=(2y²+2y)/2y²
=1+1/y
={(√1+y)[√(1+y)+√(1-y)]/[√(1+y)-√(1-y)][√(1+y)+√(1-y)]}{(1+y)/y -√[(1-y²)/y²]}
={[1+y+√(1-y²)]/[(1+y)-(1-y)]}{(1+y)/y -√(1-y²)/y}
={[(1+y)+√(1-y²)]/2y}{[(1+y)-√(1-y²)]/y}
=[(1+y)²-(1-y²)]/2y²
=(2y²+2y)/2y²
=1+1/y
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