解一元一次方程(1)x-50/3=x+70/5 (2)y-y-1/2=2-y-2/5 (3)5x-1/4=3x+1/2-

来源：学生作业帮编辑：百度作业网作业帮分类：数学作业时间：2024/08/08 20:41:58

解一元一次方程(1)x-50/3=x+70/5 (2)y-y-1/2=2-y-2/5 (3)5x-1/4=3x+1/2-2-x/3 (4)3x+1/2-2=3x-2/10-2/5

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再问：你真贱
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再问：有本事你把这一题做出来，切，我看你也做不出来
再答：你是在求我做题一元一次方程我还不想解呢自己不会海所

已知4[1-2(x+y)]+2[-(x+y)-5]=-14(x+y),求3x+3y的值.用一元一次方程解,谢谢... 先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-( （2x+y-1)(2x-y+1)-(3x+y)(3x-y),其中x=5分之1, 3x-2y=1 4x-5y （x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3) 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 化简求值{(x=2y)(5x-2y)-(3x+2y)(3x-2y)]/4x,其中x=2,y=-1 解方程组{(x-2)(y+3)=(x+1)(y-1) {(x+1)(y+1)=(x-1)(y+5) 解方程组：（0.2x+0.1y）/2- （4x-y）/10=（x-y）/5+ (3x+0.5y)/30 (3x+2y-1