.(2mn+1)(2mn-1)-(2m² n ²+2)怎么算啊 谁能列个等式出来

（1）-8m²n²+2mn-16mn² （4mn²+3m²n-4m)-2(mn²+3/2m²n+1)化简 先化简（m/m-n-n/m+n+2mn/m²-n²)²÷m²+mn/m,若m=1 计算(-2mn)^3(mn+1/2)(m^2n^2-1/2mn+1/4) 4-m²n²+2mn (3m-2n)²+24mn 因式分解(mn+m)2-(n+1)2 已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值 已知｜m-n-2｜与（mn-1)^互为相反数,求（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值 若m-n=4,mn=-1求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn) 若m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值 已知m-n=3,mn=-1,求多项式-2mn+2m+3n-3mn-2n+2m-4n-m-mn的值